Question

例如：

a = ['The', 'man', 'is', 'eating', 'pear']

eating和pear是连续的

b = ['these', 'are', 'random', 'words', 'but', 'they', 'have', 'pear', 'and', 'eating']

这是一个随机的单词列表，我想检查两个CONSECUTIVE单词是否是b中的单词

我如何制作像

这样的列表

c = ['eating', 'pear']

Answer 1

c = [(x,y) for x, y in zip(a[0:], a[1:]) if x in b and y in b]
print(c)

Answer 2

循环将

a = ['The', 'man', 'is', 'eating', 'pear', "these", "words", "mean", "nothing", "but", "words"]
b = ['these', 'are', 'random', 'words', 'but', 'they', 'have', 'pear', 'and', 'eating']

#make b a set to improve lookup times
set_b = set(b)
#list for the words found
consec = []
for i, item in enumerate(a[:-1]):
    #check consecutive words
    if item in set_b and a[i + 1] in set_b:
        #append pair if both words are in b
        consec.extend(a[i:i + 2])

#remove double entries by converting the list to a set        
print(set(consec)) 
#output is a set of words
#{'pear', 'words', 'eating', 'these', 'but'}

如果应保留a的词序，您可以执行以下操作：

a = ['The', 'man', 'is', 'eating', 'pear', "these", "mean", "nothing", "but", "words"]
b = ['these', 'are', 'random', 'words', 'but', 'they', 'have', 'pear', 'and', 'eating']

set_b = set(b)
consec = []

for i, item in enumerate(a[:-1]):
    if item in set_b and a[i + 1] in set_b:
        #first word already in list?
        if item in consec:
            #include only second word
            consec.append(a[i + 1])
        else:
            #add the pair of words
            consec.extend(a[i:i + 2])

print(consec)
#output
#['eating', 'pear', 'these', 'but', 'words']

Python检查列表中的两个连续单词是否是另一个列表中的单词

2 个答案: