Question

prblm = input("Input the Blackout math problem: ")
#I'm using  2//4=5 

OP = ['+', '-', '*', '/']  

def validate():

    """Checks to see if a string is valid"""
        for c in prblm:
            if c in OP and c+1 in OP:
                print('a')

运行时显示：

TypeError: Can't convert 'int' object to str implicitly

它应打印出'a'

如何修复该功能，或如何检查列表中是否有两个连续的字符？

Answer 1

使用ord和chr函数获取后续字符：

def validate():
    """Checks to see if a string is valid"""
        for c in prblm:
            if c in OP and chr(ord(c)+1) in OP:
                print('a')

Answer 2

正如@AlexCampbell在他的问题编辑中所述：

prblm = input("Input the Blackout math problem: ")
#I'm using  2//4=5 

OP = ['+', '-', '*', '/']  

def validate():

    """Checks to see if a string is valid"""
        for c in range (0, len(prblm)-2):
            if c in OP and c+1 in OP:
                print('a')

修正了它。不得不使用范围功能。之前：c现在是el：使用c 如在迭代器中

检查列表中是否有两个连续的字符

2 个答案: