Question

我是新手，我正在尝试将数据插入多个表

$prisoner_insert = "INSERT INTO prisoner (givenName,middleName,lastName,nickname,presentAdd,permanentAdd,prisonno,age,
        gender,civilstatus,birthdate,birthplace,height,weight,build,eyecolor,haircolor,complexion,nationality,religion,acrno,
        education,occupation,motherName,fatherName,spouse,childno,nearestkin,relationkin,kinAdd,status) 

        VALUES ('$gname','$mname','$lname','$aname','$padd','$pedd','$pno','$age','$gender','$cstatus','$bdate','$bplace',
        '$height','$weight','$build','$ecolor','$hcolor','$complex','$nation','$relign','$acr','$edu','$occu','$mother','$father','$spouse',
        '$child','$kname','$krelation','$kaddress','$status')";

$offense_insert = "INSERT INTO offensedata (crime,crimedate,caseno,trialcourt,date_sentence,datetime_commited,imprisonment)
                    VALUES ('$c_com','$c_date','$c_caseno','$trialc','$d_commence','$dt_committed','$imprisonment')";


 if(mysqli_multi_query($prisoner_insert, $offense_insert)){                       

 echo "Inserted Successfully!";
}
else{

     echo "Error:" . "<br>" . $connect->error;
}

我收到以下错误：

mysqli_multi_query（）期望参数1为mysqli，字符串为 C：\ XAMPP \ htdocs中\ jailbsystem \管理员\ admin_add.php

Answer 1

您需要在db link的第一个参数处传递mysqli_multi_query();，如下面的代码所示。

此外，您需要以正确的方式组合您的SQL查询。使用;作为每个命令的分隔符。

删除了之前的变量$prisoner_insert，$offense_insert，并将其替换为只有一个$jail_sql。

来自offensedata INSERT的prisoner_id未提供prisoner的INSERT。作为修复，在offensedata中添加了LAST_INSERT_ID（）作为字段prisoner_id的值;

LAST_INSERT_ID()提供整个数据库连接最近自动生成的ID的ID。

更新代码：

$jail_sql = "INSERT INTO prisoner (givenName,middleName,lastName,nickname,presentAdd,permanentAdd,prisonno,age,
        gender,civilstatus,birthdate,birthplace,height,weight,build,eyecolor,haircolor,complexion,nationality,religion,acrno,
        education,occupation,motherName,fatherName,spouse,childno,nearestkin,relationkin,kinAdd,status) 

        VALUES ('$gname','$mname','$lname','$aname','$padd','$pedd','$pno','$age','$gender','$cstatus','$bdate','$bplace',
        '$height','$weight','$build','$ecolor','$hcolor','$complex','$nation','$relign','$acr','$edu','$occu','$mother','$father','$spouse',
        '$child','$kname','$krelation','$kaddress','$status');";

$jail_sql .= "INSERT INTO offensedata (prisoner_id, crime,crimedate,caseno,trialcourt,date_sentence,datetime_commited,imprisonment)
                    VALUES (LAST_INSERT_ID() , '$c_com','$c_date','$c_caseno','$trialc','$d_commence','$dt_committed','$imprisonment');";


 if(mysqli_multi_query($conn, $jail_sql)){                       

 echo "Inserted Successfully!";
}
else{

     echo "Error:" . "<br>" . $connect->error;
}

mysqli_multi_query（）期望参数1为mysqli

1 个答案: