Question

我已经搜索了正确的答案，但没有一个帮助我解决这个错误。我有一个名为profile.php的页面，其中有3个不同的选项卡，其中包含从mysqli数据库生成的一些信息。问题是我必须在第三个标签中显示我已编写一些代码的订单。如果没有订单，则应输出“到目前为止没有订单!!”。它显示消息但它也显示警告。

警告：mysqli_num_rows（）要求参数1为mysqli_result，在第211行的D：\ XAMPP \ htdocs \ WebProject \ profile.php中给出布尔值

以下是第三个标签的代码。

代码

<div id="menu3" class="tab-pane fade">
 <h3>My Orders</h3>
 <?php
 $q="select customers.*, orders.date,orders.status from orders inner join customers on orders.customerid=customers.serial_cust where customers.email='$email'" ;
 $result=mysqli_query($con,$q);
  if(mysqli_num_rows($result)>0){
  while($row=mysqli_fetch_array($result))
  {
   $custid=$row['serial_cust'];
    $ordersdate=$row['date'];
   echo "<tr>";
    echo "<h3>".$row['date']."</h3>";
    echo "<h3> Status: Dispatched -> </h3> <p>".$row['status']."</p>";
     echo"<table border='1'>";
     $query="select customers.*, order_detail.*,orders.date,orders.customerid,products.* from order_detail inner join orders on orders.serial=order_detail.orderid inner join products on products.productid=order_detail.productid  inner join customers on orders.customerid=customers.serial_cust where customers.serial_cust='$custid' and orders.date='$ordersdate' ";
     $sql=mysqli_query($con,$query);
     while($row=mysqli_fetch_array($sql))
     {
     ?>
     <tr>
     <td><image width="80px" height="90px" src="assets/<?php echo $row['product_image'] ?>"/></td>
     <td><?php echo $row['product_name']. " * ". $row['quantity']?></td>
      <td><?php echo $row['color'] ?></td>
       <td><?php echo $row['price'] ?></td>
        <td><?php echo $row['size'] ?></td>
        </tr>
    <?php
      }
      echo "</table>";
     }
     }
  else{
     echo "You have not place any orders yet!";
       }
       ?>
      </div>

Answer 1

您的请求中可能存在错误。使用此代码进行调试：

$q="select customers.*, orders.date,orders.status from orders inner join customers on orders.customerid=customers.serial_cust where customers.email='$email'" ;
$result=mysqli_query($con,$q);
if (!$result)
    echo(mysqli_error($con));

if(mysqli_num_rows($result)>0){
...
}

mysqli_num_rows（）期望参数1为mysqli_result，

1 个答案: