Question

假设我要解析以下XML文件：

 <EmployeeDetails>
     <Employee>        //List of Employees
      <Id>11</Id>
      <name>a</name>
      <Dependents>    //List of Dependents of a single employee
        <Dependent>
          <name>a1</name>
          <age>50</age>      
        </Dependent>
        <Dependent>
          <name>a2</name>
          <age>52</age>      
        </Dependent>
      </Dependents>
      <Department>           //Unique per Emp
        <DeptId>1</DeptId>
        <DeptName>D1</DeptName>   
      </Department>
    </Employee>
    <Employee>
     -----
    --------
    </Employee>
   </EmployeeDetails>

以下是上述文件的类结构：

public class Employee
{
  public int id {get; set;}
  public string name {get; set;}
  public List<Dependents> Dependents {get; set;}
  public Department Department {get; set;}
}

public class Dependents
{
  public string name {get; set;}
  public int age {get; set;}
}

public class Department
{
  public int DeptId {get; set;}
  public string DeptName {get; set;}
}

现在，我想解析上面的XML结构，我能够为id的{{1}}和name进行解析，但我无法进一步解析。

让我告诉你到目前为止我做了什么：

Employee

所以我需要帮助来解析这些public static void ParseXml() { string xmldoc = //let's assume I've data in this string XDocument xdoc = new XDocument(); xdoc = XDocument.Parse(xmldoc); var query = from d in xdoc.Root.Descendants("Employee") select d; List<Employee> lsEmp = new List<Employee>(); foreach (var q in query) { Employee obj = new Employee(); obj.Id = Convert.ToInt32(q.Element("Id").Value); obj.name = q.Element("name").Value; obj.Department = new Department(); obj.Dependents = new List<Dependents>(); // how to get data further? lsEmp.Add(obj); }和Dependents对象列表中的XML数据。

Answer 1

遵循您自己的结构，这是继续解析您需要的数据的方法。

// how to get data further?
var allDependents = q.Elements("Dependents").Elements("Dependent");

foreach (var b in allDependents)
{
    Dependents d = new Dependents
    {
        age = Convert.ToInt32(b.Element("age").Value),
        name = b.Element("name").Value
    };
    obj.Dependents.Add(d);
}

obj.Department.DeptId = Convert.ToInt32(q.Element("Department").Element("DeptId").Value);
obj.Department.DeptName = q.Element("Department").Element("DeptName").Value;

请注意，我已使用.Elements("")获取Dependents

下的所有子节点

Answer 2

也许这可以帮到你：

XDocument xdoc = new XDocument();
        xdoc = XDocument.Parse(xmldoc);

        var query = from d in xdoc.Root.Descendants("Employee")
                    select d;

        List<Employee> lsEmp = new List<Employee>();

        foreach (var q in query)
        {
            Employee obj = new Employee();
            obj.Id = Convert.ToInt32(q.Element("Id").Value);
            obj.name = q.Element("name").Value;


            obj.Department = new Department()
            {
                DeptName = q.Element("Department").Element("name").Value,
                DeptId = 
               Convert.ToInt32(q.Element("Department").Element("age").Value)
            };
            obj.Dependents = new List<Dependents>();


            foreach (var e in q.Element("Dependents").Elements("Dependent"))
            {
                var dependent = new Dependents()
                {
                    name = e.Element("name").Value,
                    age = Convert.ToInt32(e.Element("age").Value)
                };
                obj.Dependents.Add(dependent);
            }

            lsEmp.Add(obj);
        }

Answer 3

以下是仅使用linq和no for for循环的代码

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.IO;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            string xml = File.ReadAllText(FILENAME);
            ParseXml(xml);

        }
        public static void ParseXml(string xml)
        {

            XDocument xdoc = XDocument.Parse(xml);

            List<Employee> employees = xdoc.Descendants("Employee").Select(x => new Employee () {
                id = (int)x.Element("Id"),
                name = (string)x.Element("Name"),
                Department = x.Elements("Department").Select(y => new Department() { DeptId = (int)y.Element("DeptId"), DeptName = (string)y.Element("DeptName")}).FirstOrDefault(),
                Dependents = x.Descendants("Dependent").Select(y => new Dependents() { age = (int)y.Element("age"),  name = (string)y.Element("name")}).ToList()
            }).ToList();
        }


    }
    public class Employee
    {
        public int id { get; set; }
        public string name { get; set; }
        public List<Dependents> Dependents { get; set; }
        public Department Department { get; set; }
    }

    public class Dependents
    {
        public string name { get; set; }
        public int age { get; set; }
    }

    public class Department
    {
        public int DeptId { get; set; }
        public string DeptName { get; set; }
    }

}

使用Multiple List＆amp; amp解析XML数据。 C＃中使用LINQ-To-XML的类对象

3 个答案: