我想将保存的xml加载到特定列表中。目前，它只是加载2个SceneObjects。我不是100％确定正确构造的xml文件或此时的代码。如果有人能够指出我正确的方向，我会很感激。我已经研究过可能将3个类合并为1来创建xml以及其他一些可能性（linq），这些可能性在我的编码级别之后有点超出我的编码水平。我正在写项目来学习我的能力。谢谢！ XML和代码如下。
代码：
private void btnOpenFile_Click(object sender, EventArgs e)
{
Stream myStream = null;
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
openFileDialog1.Filter = "XML Files (*.xml)|*.*";
openFileDialog1.FilterIndex = 1;
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = openFileDialog1.OpenFile()) != null)
{
using (myStream)
{
//create the XmlReaderSettings object
XmlReaderSettings settings = new XmlReaderSettings();
settings.IgnoreWhitespace = true;
settings.IgnoreComments = true;
//create the xml reader object
XmlReader xmlIn = XmlReader.Create(myStream, settings);
//read past all nodes until the first SceneObject node
if (xmlIn.ReadToDescendant("SceneObject"))
{
//create one waypoint object for each node
do
{
SceneObject sceneObject = new SceneObject();
xmlIn.ReadStartElement("SceneObject");
sceneObject.RunMethod = xmlIn.ReadElementContentAsString();
sceneObject.Name = xmlIn.ReadElementContentAsString();
sceneObject.Paint = xmlIn.ReadElementContentAsString();
sceneObject.Latitude = xmlIn.ReadElementContentAsDouble();
sceneObject.Longitude = xmlIn.ReadElementContentAsDouble();
sceneObject.Altitude = xmlIn.ReadElementContentAsInt();
sceneObject.Pitch = xmlIn.ReadElementContentAsDouble();
sceneObject.Bank = xmlIn.ReadElementContentAsDouble();
sceneObject.Heading = xmlIn.ReadElementContentAsDouble();
sceneObject.OnGround = Convert.ToByte(xmlIn.ReadElementContentAsString());
sceneObject.Airspeed = Convert.ToUInt32(xmlIn.ReadElementContentAsString());
sceneObjectList.Add(sceneObject);
}
while (xmlIn.ReadToNextSibling("SceneObject"));
}
//read past all nodes until the first Waypoint node
if (xmlIn.ReadToDescendant("Waypoint"))
{
//create one waypoint object for each node
do
{
Waypoint waypoint = new Waypoint();
xmlIn.ReadStartElement("Waypoint");
waypoint.Id = xmlIn.ReadElementContentAsInt();
waypoint.Flags = Convert.ToUInt32(xmlIn.ReadElementContentAsString());
waypoint.Latitude = xmlIn.ReadElementContentAsDouble();
waypoint.Longitude = xmlIn.ReadElementContentAsDouble();
waypoint.Altitude = xmlIn.ReadElementContentAsDouble();
waypoint.Speed = xmlIn.ReadElementContentAsDouble();
waypoint.Count = xmlIn.ReadElementContentAsInt();
wayPointList.Add(waypoint);
}
while (xmlIn.ReadToNextSibling("Waypoint"));
}
//read past all nodes until the first FlightPlan node
if (xmlIn.ReadToDescendant("FlightPlan"))
{
//create one flightplan object for each node
do
{
FlightPlan flightPlan = new FlightPlan();
xmlIn.ReadStartElement("FlightPlan");
flightPlan.Name = xmlIn.ReadElementContentAsString();
flightPlan.Paint = xmlIn.ReadElementContentAsString();
flightPlan.Flight = xmlIn.ReadElementContentAsString();
flightPlanList.Add(flightPlan);
}
while (xmlIn.ReadToNextSibling("FlightPlan"));
}
xmlIn.Close();
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message, "FlighT");
}
}
}
XML：
<?xml version="1.0" encoding="utf-8"?>
<Scene>
<SceneObjects>
<SceneObject>
<RunMethod>AICreateSimulatedObjectVehicle</RunMethod>
<Name>Veh_Air_BagTractor_Euro_White_sm</Name>
<Paint />
<Latitude>55.3579907547104</Latitude>
<Longitude>-131.714398095813</Longitude>
<Altitude>92</Altitude>
<Pitch>0</Pitch>
<Bank>0</Bank>
<Heading>111</Heading>
<Onground>1</Onground>
<Airspeed>0</Airspeed>
</SceneObject>
<SceneObject>
<RunMethod>AICreateSimulatedObjectVehicle</RunMethod>
<Name>VEH_Air_BagLoaderGrey</Name>
<Paint />
<Latitude>55.3579907547104</Latitude>
<Longitude>-131.714398095813</Longitude>
<Altitude>92</Altitude>
<Pitch>0</Pitch>
<Bank>0</Bank>
<Heading>111</Heading>
<Onground>1</Onground>
<Airspeed>0</Airspeed>
</SceneObject>
</SceneObjects>
<Waypoints>
<Waypoint>
<Id>1</Id>
<Flags>4</Flags>
<Latitude>55.3579907547104</Latitude>
<Longitude>-131.714398095813</Longitude>
<Altitude>92</Altitude>
<Speed>12</Speed>
<Count>0</Count>
</Waypoint>
<Waypoint>
<Id>1</Id>
<Flags>4</Flags>
<Latitude>55.3579907547104</Latitude>
<Longitude>-131.714398095813</Longitude>
<Altitude>92</Altitude>
<Speed>12</Speed>
<Count>1</Count>
</Waypoint>
</Waypoints>
<FlightPlans>
<FlightPlan>
<Name>Beech_King_Air_350</Name>
<Paint>Beech King Air 350 Paint1</Paint>
<Flight>IFR Ketchikan Intl to Annette Island</Flight>
</FlightPlan>
</FlightPlans>
</Scene>
答案 0 :(得分：0)
您是否考虑过使用AutoMapper。
Scott Toberman提供了一个很好的codeplex tutorial，它表明您可以将XML映射到列表。这是一个有点过时，但给出一个很好的概述。 Stan Bashtavenko的另一个here可能会有所帮助。
另一条路径是使用XSD.exe工具使用c＃序列化来生成ckarras建议的所需对象结构和XML架构。
答案 1 :(得分：0)
根据创建列表的目的，您可能会发现使用DataTables会更好。 DataSet将加载/写入您的xml文件，将数据存储在DataTables中。一旦进入数据表，您就可以按照您希望，编辑，显示等方式处理数据。
答案 2 :(得分：0)
您可以按照这个简单的步骤进行操作
1.Please Add using System.Xml as a reference;
2.Make a class named book in this way
public class book
{
public Nullable<System.DateTime> date{ get; set; }
public decimal price { get; set; }
public string title { get; set; }
public string description { get; set; }
}
try
{
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load("Write down full path");
XmlNodeList dataNodes = xmlDoc.SelectNodes("/catalog");
foreach (XmlNode node in dataNodes)
{
book objbook = new book();
objbook.date=Convert.ToDateTime(node.Attributes["date"].Value);
objbook.title=node.SelectSingleNode("title").InnerText;
objbook.description=node.SelectSingleNode("description").InnerText;
objbook.price=Convert.ToDecimal(node.SelectSingleNode("price").InnerText);
}
}
catch(Exception ex)
{
throw ex;
}
这里我使用一个类，你可以创建另一个类。在序列化时，然后将序列化数据分配给两个类的对象。