Question

def MasterMind():

    import random
    tries = 10
    numbers_correct = 0
    password = random.randint(1,5),random.randint(1,5),random.randint(1,5),random.randint(1,5), random.randint(1,5)
    while(not numbers_correct == 5 and tries > 0):
        guess = input("To access the treasure you have to guess the password!!! Guess the 5 digit password between numbers 1-5 ")
        guess=guess.split()
        numbers_correct = 0
        tries = tries - 1
        for i in range(len(password)):
            if (str(password[i]) == guess[i]):
                numbers_correct = numbers_correct + 1
    print(str(numbers_correct) + " out of 5 correct")
    print("you have " + str(tries) + " tries left")
    if numbers_correct == 5:
        print ("Congrats, you've gained access to the treasure!!!")
    else:
        print("sorry, you couldn't get to the treasure. The correct password was " + (password))


MasterMind()

我认为问题在于第11行，但我不确定。

我试图解释如何在我的univerisity教程中使用python，但我一直收到错误消息：

 Traceback (most recent call last):
  File "C:/Users/Owner/AppData/Local/Programs/Python/Python36-32/mastermind.py", line 25, in <module>
    MasterMind()
  File "C:/Users/Owner/AppData/Local/Programs/Python/Python36-32/mastermind.py", line 15, in MasterMind
    if (str(password[i]) == guess[i]):
IndexError: list index out of range

有点在泡菜中，我需要一双新的眼睛试图找到问题

Answer 1

执行此操作时：

guess = input("To access the treasure you have to guess the password!!! Guess the 5 digit password between numbers 1-5 ")
guess=guess.split()

... split()将guess转换为单词列表，以空格分隔。

因此，如果用户输入1 5 3 4 2，即五个字，您将获得列表['1', '5', '3', '4', '2']。然后你的代码不会引发异常。

但是如果用户键入15342，没有空格，那只是一个单词，您将获得列表['15342']。那么，当您尝试在循环中访问guess[1]时，已超过列表的末尾，因此您获得了IndexError。

如果您不希望用户键入空格，只需删除此行：

guess=guess.split()

当然，您可以尝试使其更智能，以便它可以接受两种类型的输入：

guess = [ch for ch in guess if ch.isdigit()]

但当然，如果用户拼写错误，您仍会收到错误，并且会为您1523而不是15234。

您可以使用try和except为该案例获取更好的错误处理，而不是IndexError查杀您的程序，但这可能超出您目前所了解的范围

MasterMind游戏中的索引超出范围

1 个答案: