我正在尝试拨打肥皂,并将我收到的答案反序列化。肥皂调用是正确的,但到目前为止我还没有管理将答案反序列化为对象。具体来说,答案中包含的XML是一系列重复数据。你猜我想要创建一个对象数组。我检查了其他类似的问题,但到目前为止还没有成功。让我们从定义整个XML开始。
<s:Envelope xmlns:s="http://www.w3.org/2003/05/soap-envelope" xmlns:a="http://www.w3.org/2005/08/addressing">
<s:Header>
<a:Action s:mustUnderstand="1">ThisIsATry/RetrieveResponse</a:Action>
</s:Header>
<s:Body>
<RetrieveResponse xmlns="ThisIsATry">
<RetrieveInsurersResult xmlns:b="http://schemas.datacontract.org/2004/07/ThisIsATry" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<b:Errors xmlns:c="http://schemas.microsoft.com/2003/10/Serialization/Arrays" />
<b:Message>Selected 2 records</b:Message>
<b:Results xmlns:c="http://schemas.microsoft.com/2003/10/Serialization/Arrays">
<c:ArrayOfKeyValueOfstringstring>
<c:KeyValueOfstringstring>
<c:Key>PersonId</c:Key>
<c:Value>1</c:Value>
</c:KeyValueOfstringstring>
<c:KeyValueOfstringstring>
<c:Key>Name</c:Key>
<c:Value>Mike</c:Value>
</c:KeyValueOfstringstring>
</c:ArrayOfKeyValueOfstringstring>
<c:ArrayOfKeyValueOfstringstring>
<c:KeyValueOfstringstring>
<c:Key>PersonId</c:Key>
<c:Value>2</c:Value>
</c:KeyValueOfstringstring>
<c:KeyValueOfstringstring>
<c:Key>Name</c:Key>
<c:Value>Henry</c:Value>
</c:KeyValueOfstringstring>
</c:ArrayOfKeyValueOfstringstring>
</b:Results>
<b:Warnings xmlns:c="http://schemas.microsoft.com/2003/10/Serialization/Arrays" />
</RetrieveInsurersResult>
</RetrieveResponse>
</s:Body>
</s:Envelope>
我需要使用的部分是:
<b:Results xmlns:c="http://schemas.microsoft.com/2003/10/Serialization/Arrays">
<c:ArrayOfKeyValueOfstringstring>
<c:KeyValueOfstringstring>
<c:Key>PersonId</c:Key>
<c:Value>1</c:Value>
</c:KeyValueOfstringstring>
<c:KeyValueOfstringstring>
<c:Key>Name</c:Key>
<c:Value>Mike</c:Value>
</c:KeyValueOfstringstring>
</c:ArrayOfKeyValueOfstringstring>
<c:ArrayOfKeyValueOfstringstring>
<c:KeyValueOfstringstring>
<c:Key>PersonId</c:Key>
<c:Value>2</c:Value>
</c:KeyValueOfstringstring>
<c:KeyValueOfstringstring>
<c:Key>Name</c:Key>
<c:Value>Henry</c:Value>
</c:KeyValueOfstringstring>
</c:ArrayOfKeyValueOfstringstring>
</b:Results>
正如你所看到的,有2个对象&#34;类型 c:ArrayOfKeyValueOfstringstring&gt; 。每个对象包含2个 c:KeyValueOfstringstring 类型的属性。最后,这些属性中的每一个都包含键和值。我需要的是一个 c:ArrayOfKeyValueOfstringstring 数组,包含一个 c:KeyValueOfstringstring 数组和相关信息。我尝试使用以下类在我的c#代码中表示这些数据:
public class ArrayOfKeyValueOfstringstring
{
[XmlElement("ArrayOfKeyValueOfstringstring")]
public KeyValueOfstringstring[] Value { get; set; }
}
public class KeyValueOfstringstring
{
[XmlElement("KeyValueOfstringstring")]
public KeyValue Pair { get; set; }
}
public class KeyValue
{
[XmlElement("Key")]
public string Key { get; set; }
[XmlElement("Value")]
public string Value { get; set; }
}
到目前为止我处理回复的方式是:
var result = client.UploadString(dataBaseConnectionString, soapTemplate); //calls the serive and brings back the XML
var document = XDocument.Parse(result); //gives back the first XML I posted in this question
var results = document.Descendants().FirstOrDefault(x => x.Name.LocalName == "Results"); //gives back the 2nd XML I posted
xmlNamespaceManager.AddNamespace("c", "http://schemas.microsoft.com/2003/10/Serialization/Arrays");
var oXmlSerializer = new XmlSerializer(typeof(SoapResponse[]));
//this part is wrong..
using (var mem = new MemoryStream(Encoding.UTF8.GetBytes(results.ToString())))
{
var responseObj = (ArrayOfKeyValueOfstringstring)oXmlSerializer.Deserialize(mem);
}
提前感谢您的帮助!
答案 0 :(得分:1)
正如所发生的那样,ArrayOfKeyValueOfstringstring
是DataContractSerializer
在序列化Dictionary<string, string>
时选择的元素名称,因此您可以更轻松地使用该序列化程序对您进行反序列化XML。
首先,介绍以下扩展方法:
public static partial class DataContractSerializerExtensions
{
public static T ToContractObject<T>(this XContainer doc, DataContractSerializer serializer = null)
{
if (doc == null)
throw new ArgumentNullException();
using (var reader = doc.CreateReader())
{
return (T)(serializer ?? new DataContractSerializer(typeof(T))).ReadObject(reader);
}
}
}
现在您可以将XML解析为List<Dictionary<string, string>>
,如下所示:
var dictionaries = document.Descendants()
.Where(d => d.Name.LocalName == "ArrayOfKeyValueOfstringstring")
.Select(d => d.ToContractObject<Dictionary<string, string>>())
.ToList();
之后您可以将字典列表映射到您首选的模型。
但是,如果出于某种原因必须使用XmlSerializer
,请引入以下扩展方法和数据模型:
public static partial class XmlSerializerExtensions
{
public static T ToObject<T>(this XContainer doc, XmlSerializer serializer = null)
{
if (doc == null)
throw new ArgumentNullException();
using (var reader = doc.CreateReader())
{
return (T)(serializer ?? new XmlSerializer(typeof(T))).Deserialize(reader);
}
}
}
[XmlRoot(ElementName = "KeyValueOfstringstring", Namespace = "http://schemas.microsoft.com/2003/10/Serialization/Arrays")]
public class KeyValueOfstringstring
{
[XmlElement(ElementName = "Key", Namespace = "http://schemas.microsoft.com/2003/10/Serialization/Arrays")]
public string Key { get; set; }
[XmlElement(ElementName = "Value", Namespace = "http://schemas.microsoft.com/2003/10/Serialization/Arrays")]
public string Value { get; set; }
}
[XmlRoot(ElementName = "ArrayOfKeyValueOfstringstring", Namespace = "http://schemas.microsoft.com/2003/10/Serialization/Arrays")]
public class ArrayOfKeyValueOfstringstring
{
[XmlElement(ElementName = "KeyValueOfstringstring", Namespace = "http://schemas.microsoft.com/2003/10/Serialization/Arrays")]
public List<KeyValueOfstringstring> KeyValueOfstringstring { get; set; }
}
反序列化如下:
var results = document.Descendants()
.Where(d => d.Name.LocalName == "ArrayOfKeyValueOfstringstring")
.Select(d => d.ToObject<ArrayOfKeyValueOfstringstring>())
.ToList();
注意:
我使用XNode.CreateReader()
返回XmlReader
,XNode
可以直接反序列化<b:Results>
。这避免了将所选节点转换回字符串表示然后重新解析的要求。
"http://schemas.datacontract.org/2004/07/ThisIsATry"
节点的命名空间为#include<stdio.h>
int main()
{
int i;
if (i <= 10)
{
for (scanf("%d", &i);i<=10;i++)
{
printf("%d\n",i);
}
}
else
{
printf("Please enter a valid number");
}
}
。这个命名空间感觉......是临时的...所以我在答案中避免使用它。
所有这些都说,既然XML似乎可能是由wcf service生成的,那么服务是否有可能提供WSDL Metadata?如果是这样,您可以自动生成客户端。见
有关如何完成此操作的文档。
答案 1 :(得分:0)
试试xml linq
pieChart.getLegend().setPosition(Legend.LegendPosition.ABOVE_CHART_LEFT);
pieChart.getLegend().setOrientation(Legend.LegendOrientation.VERTICAL);