我正在从http Web请求中检索xml数据并将数据反序列化为对象。
这是一个示例xml结构。
<users>
<user>
<name>...</name>
<orders>
<order>
<number>...</number>
</order>
...
</orders>
</user>
<user>
<name>...</name>
<orders></orders>
</user>
...
</users>
我有四个班级
public class Users
{
[XmlElement("user")]
public User[] UserList { get; set; }
}
public class User
{
[XmlElement("name")]
public string Name { get; set; }
[XmlArray("orders")]
public Orders OrderList { get; set; }
}
public class Orders
{
[XmlElement("order")]
public Order[] Order { get; set; }
}
public class Order
{
[XmlElement("number")]
public string Number { get; set; }
}
我觉得三个类应该足够了 - 在User类中有一个Order []并摆脱'Orders'类。那可能吗?无论我尝试什么都行不通。
感谢。
答案 0 :(得分:12)
这应该有效
XmlSerializer ser = new XmlSerializer(typeof(Users));
var u = (Users)ser.Deserialize(stream);
[XmlRoot("users")]
public class Users
{
[XmlElement("user")]
public User[] UserList { get; set; }
}
public class User
{
[XmlElement("name")]
public string Name { get; set; }
[XmlArray("orders"),XmlArrayItem("order")]
public Order[] OrderList { get; set; }
}
[XmlRoot("order")]
public class Order
{
[XmlElement("number")]
public string Number { get; set; }
}
答案 1 :(得分:2)
您只能使用3个课程。您所要做的就是将Xml.Serialization.XmlType添加到您的类
using System;
using System.Collections;
using System.Collections.Generic;
using System.Data;
using System.Diagnostics;
[Xml.Serialization.XmlType("users", IncludeInSchema = true)]
public class Users
{
[XmlElement("user")]
public List<User> UserList {
get {
if (m_UserList == null) {
m_UserList = new List<User>();
}
return m_UserList;
}
}
private List<User> m_UserList;
}
[Xml.Serialization.XmlType("user", IncludeInSchema = true)]
public class User
{
[XmlElement("name")]
public string Name {
get { return m_Name; }
set { m_Name = value; }
}
private string m_Name;
[XmlArray("orders")]
public List<Orders> OrderList {
get {
if (m_OrderList == null) {
m_OrderList = new List<Orders>();
}
return m_OrderList;
}
}
private List<Orders> m_OrderList;
}
[Xml.Serialization.XmlType("orders", IncludeInSchema = true)]
public class Orders
{
[XmlElement("number")]
public string Number {
get { return m_Number; }
set { m_Number = value; }
}
private string m_Number;
}