Question

错误（活动）E0289没有构造函数“std :: thread :: thread”的实例匹配参数列表

#ifndef TIMER_H
#define TIMER_H

#include <thread>
#include <chrono>

class Timer
{
std::thread Thread;
bool Alive = false;
long CallNumber = -1L;
long repeat_count = -1L;
std::chrono::milliseconds interval = std::chrono::milliseconds(0);
std::function< void(void) > funct = nullptr;

void SleepAndRun()
{
    std::this_thread::sleep_for(interval);
    if (Alive)
         Function()();
}

void ThreadFunc()
{
    if (CallNumber == Infinite)
        while (Alive)
            SleepAndRun();
    else
        while (repeat_count--)
            SleepAndRun();
}

public:
    static const long Infinite = -1L;

    Timer(){}

    Timer(const std::function<void(void)> &f) : funct (f) {}

    Timer(const std::function<void(void)> &f,
        const unsigned long &i,
        const long repeat = Timer::Infinite) : funct(f),

    interval(std::chrono::milliseconds(i)),
                                               CallNumber(repeat) {}

    void Start(bool Async = true)
    {
        if (isAlive())
            return;
        Alive = true;
        repeat_count = CallNumber;
        if (Async)
            Thread = std::thread(ThreadFunc, this);//  <- There is an error
        else
            this->ThreadFunc();
    }
    void Stop()
    {
        Alive = false;
        Thread.join();
    }
    void SetFunction(const std::function<void()> &f)
    {
        funct = f;
    }

    bool isAlive() const { return Alive; }

    void RepeatCount(const long r)
    {
        if (Alive)
            return;
        CallNumber = r;
    }
    long GetLeftCount() const { return repeat_count; }

    long RepeatCount() const { return CallNumber; }

    void SetInterval(const unsigned long &i)
    {
        if (Alive)
            return;
        interval = std::chrono::milliseconds(i);
    }
    unsigned long Interval() const { return interval.count(); }

    const std::function<void(void)> &Function() const
    {
        return funct;
    }
};

#endif // !TIMER_H

严重级代码描述项目文件行抑制状态错误C3867'Timer :: ThreadFunc'：非标准语法;使用'＆amp;'至创建指向成员53的指针

第53行

错误

有人可以解释这个错误是什么意思吗？

Answer 1

ThreadFunc是非静态成员函数，它需要this指针。

最简单的解决方法是传递lambda：

Thread = std::thread([this] { this->ThreadFunc(); });

或@Some程序员老兄指出：

Thread = std::thread(&Timer::ThreadFunc, this);

没有构造函数“std :: thread :: thread”的实例匹配参数列表

1 个答案: