Question

我无法弄清楚我的代码有什么问题。我正在尝试从edx完成实验室任务，但我无法弄清楚为什么我的代码无法正常工作。作业需要创建Student类，Teacher类和Course类。我试图找出Course类的构造函数，但它不会接受我的Teacher对象。我使用指针创建对象，以便为内存分配空间（我在edx上学到的东西之一，告诉我，如果我误解了）。所以我尝试在构造函数中使用引用，但它仍然无效。这是代码。我使用＆＃34; unknown＆＃34;作为填充物。

主要代码：

#include "stdafx.h"
#include <iostream>
#include <string>
#include "Student.h"
#include "Teacher.h"
#include "Course.h"

using namespace std;

int main()
{
    Teacher *teach = new Teacher("Jane", "DoeDoe", 25, "Unknown", "Unknown", "Unknown");
    Student *stud1 = new Student();
    Student *stud2 = new Student("John", "Doe", 19, "Unknown", "Unknown", "Unknown");
    Student *stud3 = new Student("Jane", "Doe", 23, "Unknown", "Unknown", "Unknown");
    //Method had two postions. First and Last
    stud1->setName("Unknown", "Unknown");
    stud1->setAge(20);
    stud1->setAddress("Unknown");
    stud1->setCity("Unknown");
    stud1->setPhone("Unknown");

    Course *c = new Course("Intermediate C++", teach, stud1, stud2, stud3);


    return 0;
}

Course.h

#pragma once

#include <iostream>
#include "Student.h"
#include "Teacher.h"
#include <string>

using namespace std;

class Course {
private:
    string name;
    Teacher teacher;
    Student student1;
    Student student2;
    Student student3;


public:


    Course(string n, Teacher &t, Student &s1, Student &s2, Student &s3);

    ~Course();


};

Course.cpp

#include "stdafx.h"
#include "Course.h"



Course::Course(string n, Teacher &t, Student &s1, Student &s2, Student &s3)
{
    name = n;
    teacher = t;
    student1 = s1;
    student2 = s2;
    student3 = s3;

}

Course::~Course()
{
}

Answer 1

@Component.Invoke()

希望您将引荐传递给Course(string n, Teacher &t, Student &s1, Student &s2, Student &s3);，t，s1 ..

s2

在这里传递Course *c = new Course("Intermediate C++", teach, stud1, stud2, stud3); teach。你想要

teacher*

您可能想要了解有关references and pointers

的更多信息

C ++没有构造函数的实例匹配参数列表。

1 个答案: