我正在尝试根据从第5行开始的第L列中的键到L中的第一个空白单元格将大范围(D:AX)添加到字典中。代码当前设置为从列L获取值和斧头。如何修改此代码以使用L作为键将值D:AX添加到字典中?任何帮助表示赞赏!
renderItem = (item, parentNavigate) => (
<TouchableOpacity onPress={parentNavigate('Details')} >
<View style={{width: 136}}>
...
<Text>some text</Text>
</View>
</TouchableOpacity>
);
const Strip = (props, parentNavigate) => {
return Object.keys(props).map(function(key, i) {
return Object.keys(props[key]).map((strips, i) => {
var strip = props[key][strips];
return(
<View>
<Text>{strip.title}</Text>
<FlatList horizontal
data={strip.someobjects}
renderItem={(item, parentNavigate) => this.renderItem(item, parentNavigate)}
/>
</View>
)
});
})
}
答案 0 :(得分:1)
类似的东西:
Option Explicit
Sub TEST()
Dim dict As Object
Dim last As Long
Set dict = CreateObject("Scripting.Dictionary")
With ThisWorkbook.Worksheets("Sheet1")
If .Cells(.Rows.Count, "L").End(xlUp).Row > 5 Then
last = .Cells(.Rows.Count, "L").End(xlUp).Row
Else
last = 5
End If
Dim rData As Range
Set rData = .Range("L5:L" & last & ",AX5:AX" & last)
Dim i As Long
For i = rData.Row To rData.Row + rData.Rows.Count - 1
If Not IsEmpty(.Cells(i, "L")) And Not dict.Exists(.Cells(i, "L").Value) Then
dict.Add .Cells(i, "L").Value, .Range(.Cells(i, "D"), .Cells(i, "AX")).Value
End If
Next i
' .Parent.Close False
Dim columnCount As Long
columnCount = .Range(.Cells(i, "D"), .Cells(i, "AX")).Columns.Count
End With
Dim key As Variant
Dim counter As Long
For Each key In dict.keys
counter = counter + 1
Worksheets("Sheet2").Range("A" & counter).Resize(1, columnCount) = dict(key)
Next key
End Sub
如果将值存储为数组而不是范围
Dim fso As Object
Set fso = CreateObject("Scripting.FileSystemObject")
Dim Fileout As Object
Set Fileout = fso.CreateTextFile("C:\Users\User\Desktop\Test\Test.txt", True, True)
Dim n As Long
For Each key In dict.keys
For n = 1 To UBound(dict(key), 2)
Fileout.WriteLine dict(key)(1, n)
Next n
Next key
Fileout.Close
写出txt文件:
content= fopen('text file.txt');
for i=1:size(content,1) *%loop to read till the end of the matrix*
variable_part(i) = fgetl(fid); *%read row and create the integer value in the dynamic variable.*
for i=1 *% loop through the matrix that contains all the created dynamic variables one by one and perform these.*
for i=1:size(variable_part(i),1)
a= variable_part(i)(i,:);
variable_part(i,1)= mean(a);
variable_part(i,2)= min(a);
variable_part(i,3)= max(a);
variable_part(i,4)= std(a);
variable_part(i,5)= var(a);
variable_part(i,6)= max(a)-min(a);
end;
end;
end;