Question

数组数据是混合的我希望重复日期并在数组中连接数字

var data = [
    ['mars 21 21:37', 624],
    ['mars 21 21:37', 599],
    ['mars 21 21:37', 636],
    ['mars 21 21:37', 619],
    ['mars 21 21:37', 625],
    ['mars 21 21:37', 645],
    ['mars 21 21:37', 638],
    ['mars 21 23:24', 733],
    ['mars 21 23:24', 800],
    ['mars 21 23:24', 609],
    ['mars 21 23:24', 615],
    ['mars 22 09:20', 550],
    ['mars 22 09:20', 608],
    ['mars 22 09:20', 609]
];

我正在寻找转化为

的解决方案

var data = [{
    'mars 21 21:37': [624, 599, 636, 619, 625, 645, 638],
    'mars 21 23:24': [733, 800, 609, 615],
    'mars 22 09:20': [550, 608, 609]
}];

任何想法？

Answer 1

你可以这样做：

var data = [
  [ 'mars 21 21:37', 624 ],
  [ 'mars 21 21:37', 599 ],
  [ 'mars 21 21:37', 636 ],
  [ 'mars 21 21:37', 619 ],
  [ 'mars 21 21:37', 625 ],
  [ 'mars 21 21:37', 645 ],
  [ 'mars 21 21:37', 638 ],
  [ 'mars 21 23:24', 733 ],
  [ 'mars 21 23:24', 800 ],
  [ 'mars 21 23:24', 609 ],
  [ 'mars 21 23:24', 615 ],
  [ 'mars 22 09:20', 550 ],
  [ 'mars 22 09:20', 608 ],
  [ 'mars 22 09:20', 609 ]
];

let output = {};
data.forEach(([key, value]) => {
    if (Array.isArray(output[key])) {
        output[key].push(value);
    } else {
        output[key] = [value];
    }
})

console.log(output);

如果你在减少之后，你可以做这样的事情：

var data = [
  ['mars 21 21:37', 624],
  ['mars 21 21:37', 599],
  ['mars 21 21:37', 636],
  ['mars 21 21:37', 619],
  ['mars 21 21:37', 625],
  ['mars 21 21:37', 645],
  ['mars 21 21:37', 638],
  ['mars 21 23:24', 733],
  ['mars 21 23:24', 800],
  ['mars 21 23:24', 609],
  ['mars 21 23:24', 615],
  ['mars 22 09:20', 550],
  ['mars 22 09:20', 608],
  ['mars 22 09:20', 609]
];

data = data.reduce((carry, [key, value]) => {
  if (Array.isArray(carry[key])) {
    carry[key].push(value)
  } else {
    carry[key] = [value]
  }
  return carry;
}, {});

console.log(data)

// If you're after the super compressed version you could do this:
// data = data.reduce((c,[k,v])=>(c[k]=[...(c[k]||[]),v],c),{});

Answer 2

您可以将Array.prototype.reduce()与Array.prototype.concat()结合使用：

＆＃13;

const data = [['mars 21 21:37', 624],['mars 21 21:37', 599],['mars 21 21:37', 636],['mars 21 21:37', 619],['mars 21 21:37', 625],['mars 21 21:37', 645],['mars 21 21:37', 638],['mars 21 23:24', 733],['mars 21 23:24', 800],['mars 21 23:24', 609],['mars 21 23:24', 615],['mars 22 09:20', 550],['mars 22 09:20', 608],['mars 22 09:20', 609]];
const result = data.reduce((a, [d, v]) => (a[d] = a[d] ? a[d].concat(v) : [v], a), {});

console.log(result);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 3

您可以使用reduce方法并返回一个对象。

＆＃13;

var data = [ [ 'mars 21 21:37', 624 ],[ 'mars 21 21:37', 599 ],[ 'mars 21 21:37', 636 ],[ 'mars 21 21:37', 619 ],[ 'mars 21 21:37', 625 ],[ 'mars 21 21:37', 645 ],[ 'mars 21 21:37', 638 ],[ 'mars 21 23:24', 733 ],[ 'mars 21 23:24', 800 ],[ 'mars 21 23:24', 609 ],[ 'mars 21 23:24', 615 ],[ 'mars 22 09:20', 550 ],[ 'mars 22 09:20', 608 ],[ 'mars 22 09:20', 609]];
  
const result = data.reduce((r, [time, value]) => {
  if(!r[time]) r[time] = [value]
  else r[time].push(value);
  return r;
}, {})

console.log(result)

＆＃13;

Answer 4

您可以使用函数reduce来构建所需的输出。

var data = [ [ 'mars 21 21:37', 624 ],  [ 'mars 21 21:37', 599 ],  [ 'mars 21 21:37', 636 ],  [ 'mars 21 21:37', 619 ],  [ 'mars 21 21:37', 625 ],  [ 'mars 21 21:37', 645 ],  [ 'mars 21 21:37', 638 ],  [ 'mars 21 23:24', 733 ],  [ 'mars 21 23:24', 800 ],  [ 'mars 21 23:24', 609 ],  [ 'mars 21 23:24', 615 ],  [ 'mars 22 09:20', 550 ],  [ 'mars 22 09:20', 608 ],  [ 'mars 22 09:20', 609 ] ],
    result = data.reduce((a, [date, value]) => ((a[date] || (a[date] = [])).push(value), a), {});
console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 5

您可以先使用underscore.js链式方法进行分组，然后再简化收集的值。

＆＃13;

var data = [['mars 21 21:37', 624], ['mars 21 21:37', 599], ['mars 21 21:37', 636], ['mars 21 21:37', 619], ['mars 21 21:37', 625], ['mars 21 21:37', 645], ['mars 21 21:37', 638], ['mars 21 23:24', 733], ['mars 21 23:24', 800], ['mars 21 23:24', 609], ['mars 21 23:24', 615], ['mars 22 09:20', 550], ['mars 22 09:20', 608], ['mars 22 09:20', 609]];
  
console.log(_
    .chain(data)
    .groupBy(([date]) => date)
    .mapObject(values => values.map(([, v]) => v))
    .value()
);

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>

＆＃13;

如何从数组和concat数据中重复索引索引

5 个答案: