Question

我在SQL Server中将一些数据存储为XML，如下所示：

<FormSearchFilter>
    .......
    <IDs>
        <int>1</int>
        <int>2</int>
    </IDs>
    .......
</FormSearchFilter>

此XML映射到DTO，ID的数据类型正在从List更改为字符串。因此，我现在需要更新所有现有XML：数据，如下所示：

<FormSearchFilter>
    .......
    <IDs>1,2</IDs>
    .......
</FormSearchFilter>

通过更新查询实现此目的的最佳方式

Answer 1

除了提示，这是一个非常糟糕的主意！你可能会尝试这样的事情：

DECLARE @t TABLE(
 Id INT NOT NULL IDENTITY(1,1),
 xml XML)

INSERT INTO @t(xml)
VALUES
 ('<FormSearchFilter><IDs><int>1</int><int>2</int></IDs></FormSearchFilter>'),
 ('<FormSearchFilter><IDs><int>1</int><int>2</int><int>3</int></IDs></FormSearchFilter>'),
 ('<FormSearchFilter><IDs><int>1</int><int>2</int><int>3</int><int>4</int></IDs></FormSearchFilter>');

 UPDATE @t
 SET [xml]= (SELECT REPLACE([xml].query('data(/FormSearchFilter/IDs/int)').value('.','nvarchar(max)'),' ',',') AS IDs 
             FOR XML PATH('FormSearchFilter'));

 SELECT * FROM @t

说明：

XQuery函数data()将返回由空格分隔的alle text()个节点（在您的情况下为int值）。可以用逗号替换它以获取所需的列表。

更新：保留其他元素（请注意，订单更改）

INSERT INTO @t(xml)
VALUES
 ('<FormSearchFilter><test>x</test><IDs><int>1</int><int>2</int></IDs></FormSearchFilter>'),
 ('<FormSearchFilter><IDs><int>1</int><int>2</int><int>3</int></IDs><test>x</test></FormSearchFilter>'),
 ('<FormSearchFilter><IDs><int>1</int><int>2</int><int>3</int><int>4</int></IDs></FormSearchFilter>');

 UPDATE @t
 SET [xml]= (SELECT  [xml].query('/FormSearchFilter/*[local-name()!="IDs"]') AS [*]
                    ,REPLACE([xml].query('data(/FormSearchFilter/IDs/int)').value('.','nvarchar(max)'),' ',',') AS IDs 
             FOR XML PATH('FormSearchFilter'));

 SELECT * FROM @t

Answer 2

有点骇客，如果你对帮助表值函数持开放态度。

示例

Declare @XML xml = ' <FormSearchFilter> <OtherContent>Some Content</OtherContent> <IDs> <int>1</int> <int>2</int> </IDs> <IDs> <int>11</int> <int>12</int> <int>13</int> </IDs> <IDs> <int>99</int> </IDs> <MoreContent>Some MORE Content</MoreContent> </FormSearchFilter> ' Select @XML = replace(cast(@XML as varchar(max)),RetVal,NewVal) From ( Select * ,NewVal = stuff(replace(replace(RetVal,'<int>',','),'</int>',''),1,1,'') From [dbo].[tvf-Str-Extract](cast(@XML as varchar(max)),'<IDs>','</IDs>') ) A Select @XML

<强>返回

<FormSearchFilter> <OtherContent>Some Content</OtherContent> <IDs>1,2</IDs> <IDs>11,12,13</IDs> <IDs>99</IDs> <MoreContent>Some MORE Content</MoreContent> </FormSearchFilter>

创建TVF是因为我厌倦了提取内容（左，右，charindex，patindex，反向......）。它是一个修改后的解析/拆分函数，它接受两个非类似的分隔符。只是为了说明，如果你要跑：

Select * From [dbo].[tvf-Str-Extract](cast(@XML as varchar(max)),'<IDs>','</IDs>')

结果将是

RetSeq RetPos RetVal 1 65 <int>1</int><int>2</int> 2 100 <int>11</int><int>12</int><int>13</int> 3 150 <int>99</int>

有兴趣的TVF

CREATE FUNCTION [dbo].[tvf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100)) Returns Table As Return ( with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)), cte2(N) As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ), cte3(N) As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1), cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S) Select RetSeq = Row_Number() over (Order By N) ,RetPos = N ,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1) From ( Select *,RetVal = Substring(@String, N, L) From cte4 ) A Where charindex(@Delimiter2,RetVal)>1 ) /* Max Length of String 1MM characters Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...' Select * From [dbo].[tvf-Str-Extract] (@String,'[[',']]') */

Answer 3

不是特别优雅，但最终会得到所需的输出：

DECLARE @t TABLE(
 Id INT NOT NULL IDENTITY(1,1),
 xml XML)

INSERT INTO @t(xml)
VALUES
 ('<FormSearchFilter><IDs><int>1</int><int>2</int></IDs></FormSearchFilter>'),
 ('<FormSearchFilter><IDs><int>1</int><int>2</int><int>3</int></IDs></FormSearchFilter>'),
 ('<FormSearchFilter><IDs><int>1</int><int>2</int><int>3</int><int>4</int></IDs></FormSearchFilter>');

DECLARE @updates TABLE(
 Id INT,
 UpdatedValue XML
)

INSERT INTO @updates
SELECT 
 Id,
 (SELECT STUFF((
  SELECT 
   ',' + c.value('.', 'varchar')
  FROM @t t1
   CROSS APPLY t1.xml.nodes('//IDs/int') x(c)
  WHERE t1.Id = t.Id
  FOR XML PATH('')
 ), 1, 1, '') IDs
 FOR XML PATH(''))
FROM @t t

-- remove existing IDs node
UPDATE @t
 SET xml.modify('delete //IDs')

-- insert updated IDs node back in
UPDATE t
 SET xml.modify('insert sql:column("u.UpdatedValue") into (/FormSearchFilter)[1]')
FROM @t t
 JOIN @updates u ON t.Id = u.Id

在SQL XML数据中更新节点结构

3 个答案:

说明：

更新：保留其他元素（请注意，订单更改）