我正在尝试修改拖放上传器。文件上传后,它会显示在右侧。我想在右侧为每个文件添加一个描述字段。我的XML是通过检查目录来编写的。我能够将每个文件的描述保存到XML。但如果我要删除文件或将文件上传到目录,它会用“-
”覆盖我的所有描述。我尝试做的是上传或删除新项目而不覆盖我的旧项目描述。
PHP-用于删除和上传。此功能正在检查目录并为每个已上载的文件添加XML节点。
if ( $handle = opendir( $path_to_image_dir ) )
{
while (false !== ($file = readdir($handle)))
{
if ( is_file($path_to_image_dir.'/'.$file) && $file != "." && $file != ".." && $file != "Thumb.db" && $file != "Thumbs.db" && $file != ".DS_Store" )
{
list( $width, $height ) = getimagesize($path_to_image_dir.'/'.$file);
$image = $xml_generator->addChild('image');
$image->addChild('id', 'file'.$i++);
$image->addChild('name', $file);
$image->addChild('width', $width);
$image->addChild('height', $height);
$image->addChild('description', '-');
}
}
closedir($handle);
}
// Write the XML File to a file.
$xml_generator->asXML('../file.xml');
Description.Php 将描述添加到每个项目。
$filename = "../file.xml";
//value form the pop up description form.
$description = $_POST['description'];
// id of input from the write rightside list.
$hid = $_POST['fileID'];
$xml->image ->description = $description;
$xml = simplexml_load_file($filename);
foreach($xml->image as $image)
{
// matching the xml id to input id, and then updating the description.
if ($image->id == $fileID)
{
$image->description = $description;
}
}
$xml->asXML($filename);
XML
<images>
<image>
<id>file0</id>
<name>image1.jpg</name>
<height>1435</height>
<width>2551</width>
<description>-</description>
</image>
<image>
<id>file1</id>
<name>Image2.jpg</name>
<height>1435</height>
<width>2551</width>
<description>-</description>
</image>
</images>
答案 0 :(得分:0)
我可以看到您的Description.Php
存在3个问题,首先您应该调用$hid
变量$fileID
,然后在{{$xml->image ->description = $description;
之前调用simplexml_load_file
1}}并且最后你不验证是否设置了fileID和描述。
所以你的文件应该是这样的:
$filename = "../file.xml";
//value form the pop up description form.
$description = $_POST['description'];
if (!isset($description))
die("The field description is not set.");
// id of input from the write rightside list.
$fileID = $_POST['fileID'];
if (!isset($fileID))
die("The field fileID is not set.");
$xml = simplexml_load_file($filename);
foreach($xml->image as $image)
{
// matching the xml id to input id, and then updating the description.
if ($image->id == $fileID)
{
$image->description = $description;
}
}
$xml->asXML($filename);
您还应该使用isset
或类似内容来确保POST存在。
关于你的第一个代码,会发生的事情是,如果不读取你已经拥有的XML,你就会反复为每个文件创建新的节点,并保存为新的XML覆盖旧的XML,以保留你应该做的旧描述像这样的东西:
if ( $handle = opendir( $path_to_image_dir ) )
{
while (false !== ($file = readdir($handle)))
{
if ( is_file($path_to_image_dir.'/'.$file) && $file != "." && $file != ".." && $file != "Thumb.db" && $file != "Thumbs.db" && $file != ".DS_Store" )
{
$fileID = 'file'.$i++;
list( $width, $height ) = getimagesize($path_to_image_dir.'/'.$file);
$oldImage = $xml_generator->xpath('//images/image[id="'.$fileID.'"]');
if (count($oldImage) == 0)
{
$image = $xml_generator->addChild('image');
$image->addChild('id', $fileID);
$image->addChild('name', $file);
$image->addChild('width', $width);
$image->addChild('height', $height);
$image->addChild('description', '-');
}
else
{
$oldImage = $oldImage[0];
$oldImage->name = $file;
$oldImage->width = $width;
$oldImage->height = $height;
}
}
}
closedir($handle);
}
// Write the XML File to a file.
//$xml_generator->asXML('../file.xml');
//In case it saves all in one line and u want
//to properly format the XML use:
$dom = new DOMDocument('1.0');
$dom->preserveWhiteSpace = false;
$dom->formatOutput = true;
$dom->loadXML($xml_generator->asXML());
echo $dom->save('../file.xml');