Question

我试图抓取德国政党的新闻页面并将所有信息存储在数据框中（＆＃34; python beginner＆＃34;）。当我想将整个文本甚至日期存储到数据帧中时，只存在一个小问题。看起来只有文本的最后一个元素（p ... / p）才会存储在行中。我认为问题出现是因为循环上的迭代会产生误导。

import pandas as pd
import requests 
from time import sleep
from random import randint
from time import time
import numpy as np
from urllib.request import urlopen

data = pd.DataFrame()
teaser = ()
title = []
content = ()
childrenUrls = []
mainPage = "https://www.fdp.de"
start_time = time()
counter = 0

#for i in list(map(lambda x: x+1, range(3))):
for i in range(3):

    counter = counter + 1
    sleep(randint(1,3))
    elapsed_time = time() - start_time
    print('Request: {}; Frequency: {} requests/s'.format(counter, counter/elapsed_time))
    url = "https://www.fdp.de/seite/aktuelles?page="+str(i)
    #print(url)
    r = requests.get(url)
    soup = BeautifulSoup(r.content, 'html.parser')

    uls = soup.find_all('div', {'class': 'field-title'})

    for ul in uls:
        for li in ul.find_all('h2'):
            for link in li.find_all('a'):
                url = link.get('href')
                contents = link.text
                print(contents)
                childrenUrls = mainPage+url
                print(childrenUrls)

                childrenPages = urllib2.urlopen(childrenUrls)
                soupCP = BeautifulSoup(childrenPages, 'html.parser')

                #content1 = soupCP.findAll('p').get_text()
                #print(content1)

                for content in soupCP.findAll('p'):
                    #for message in content.get('p'):
                    content = content.text.strip()
                    print(content)

                for teaser in soupCP.find_all('div', class_ = 'field-teaser'):
                    teaser = teaser.text.strip()
                    print(date)

                for title in soupCP.find_all('title'):
                    title = title.text.strip()
                    print(ttt)

                df = pd.DataFrame(
                    {'teaser': teaser,
                     'title' : title,
                    'content' : content}, index=[counter])

                data = pd.concat([data, df])
    #join(str(v) for v in value_list)

Answer 1

您必须将每个循环中的文本保存在列表中，而不是保存在简单的字符串变量中。在每次迭代中，您的代码重新定义变量的值;这导致丢失以前的数据。

一个好方法，就是在这里使用list comprehension。用以下代码替换代码的最后3 for个循环：

content = [x.text.strip() for x in soupCP.find_all('p')]
teaser = [x.text.strip() for x in soupCP.find_all('div', class_='field-teaser')]
title = [x.text.strip() for x in soupCP.find_all('title')]

df = pd.DataFrame(
    {'teaser': teaser,
     'title': title,
     'content': content}, index=[counter])

data = pd.concat([data, df])

列表理解的简单解释：

行content = [x.text.strip() for x in soupCP.find_all('p')]相当于：

content = []
for x in soupCP.find_all('p'):
    content.append(x.text.strip())

美丽的汤得到多页的文本

1 个答案: