Question

我是匿名阻止，应删除@在电子邮件列中的所有内容。

DECLARE
   v_id NUMBER(10);
   v_email VARCHAR2(30);
   i NUMBER(1) := 0;
   CURSOR cursor_name IS 
      SELECT Id, (substr (email, instr (email,'@',1) + 1 )) AS Domain
      FROM invoices
      WHERE id=31232681;
BEGIN
   OPEN cursor_name;
   LOOP
      v_email := '@' || v_email;
      FETCH cursor_name INTO v_id, v_email;
         UPDATE invoices
         SET email = v_email
         WHERE Id =  v_id;
      EXIT WHEN cursor_name%NOTFOUND
   END LOOP;
   CLOSE cursor_name;
END;

但是得到了PLS-00103错误：

PLS-00103: Encountered the symbol "(" when expecting one of the following:
     := . ) , @ % default character 
The symbol ":=" was substituted for "(" to continue

可以帮我理解是什么问题吗？

解决方案 半结肠遗失在：

退出时为cursor_name％NOTFOUND;

Answer 1

你能试试吗？

DECLARE    
 v_id NUMBER(10);
 v_email VARCHAR2(30);
 i NUMBER(1) := 0;

 CURSOR cursor_name IS 
  SELECT Id, (substr (email, instr (email,'@',1) + 1 )) AS Domain
  FROM invoices
  WHERE id=31232681;

BEGIN
 OPEN cursor_name;
 LOOP
  v_email := '@' || v_email;
  FETCH cursor_name INTO v_id, v_email;
   UPDATE invoices
   SET email = v_email
   WHERE Id =  v_id;
   EXIT WHEN cursor_name%NOTFOUND;
 END LOOP;
 CLOSE cursor_name;
END;

我现在已经看到了你的解决方案，抱歉：）

带游标的PL / SQL更新

1 个答案: