在骰子游戏中比较两个数组中相同的位置整数

Question

我希望有一个骰子游戏，用户被问到两个骰子要滚多少次。根据卷内的对，用户将获得总额的奖金。

我遇到的问题是我无法使用当前的for循环比较数组中的相同位置值。

我得到的错误是：The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

以下是代码：

import numpy as np
import random

def dice_game():

    rolls = int(input("how many times would you like to roll the dice: "))
    dice_value1 = np.random.randint( 1, 7, rolls)
    print(dice_value1)
    dice_value2 = np.random.randint( 1, 7, rolls)
    print(dice_value2)
    return dice_value1, dice_value2

result1, result2 = dice_game()

def dice_game_analysis(x,y):
    total = 0
    for i in range(len(x)):
          if i == y:
              if i == 1:
                  total = 0
              if i <= 4:
                  total += x
              if i >= 5:
                  total += 2*x
    print(total)

dice_game_analysis(result1, result2)