Question

我正在开发一个Android APP，它有一个基于短信传入消息的广播接收器。

我想跟踪来自特定senderNumber的每条消息，并使用该SMS执行某些操作，例如，从每条消息中检索一些数据。

我要分析的消息体是：

＆＃34;已使用ha recibido 5.0 CUC del numero 55391393 .Saldo principal 1565.0 CUC，linea activa hasta 2019-02-10，vence 2019-03-12＆＃34;

我想用Pattern类提取，标记为粗体的值。但我在正则表达式中真的很新。一些帮助？

这是我的实际代码：

public class SMSReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {

        final Bundle bundle = intent.getExtras();

        try {

            if (bundle != null) {

                final Object[] pdusObj = (Object[]) bundle.get("pdus");

                assert pdusObj != null;
                for (Object aPdusObj : pdusObj) {

                    SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) aPdusObj);
                    String senderNum = currentMessage.getDisplayOriginatingAddress();
                    String message = currentMessage.getDisplayMessageBody();

                    /*
                    String body = currentMessage.getMessageBody().toString();
                    String address = currentMessage.getOriginatingAddress();
                    */

                    Log.i("SmsReceiver", "senderNum: " + senderNum + "; message: " + message);

                    //Save to DB
                    if (senderNum.equals("Cubacel")) {

                        Toast.makeText(context, "senderNum: " + senderNum + ", message: " + message, Toast.LENGTH_LONG).show();

                        //Parse this SMS with Regular Expresions


                    } else {
                        //Search for transferred numbers pending
                    }

                } // end for loop

            } // bundle is null

        } catch (Exception e) {
            Log.e("SmsReceiver", "Exception smsReceiver" + e);
        }
    }
}

这是一个使用JS的示例工作代码，但我不知道如何在Java中实现 https://regexr.com/3mgq2

Answer 1

    String re1=".*?";   // Non-greedy match on filler
    String re2="(5\\.0)";   // Float 1
    String re3=".*?";   // Non-greedy match on filler
    String re4="(55391393)";    // Number 1
    String re5=".*?";   // Non-greedy match on filler
    String re6="(1565\\.0)";    // Float 2

    Pattern p = Pattern.compile(re1+re2+re3+re4+re5+re6,Pattern.CASE_INSENSITIVE | Pattern.DOTALL);

试试这个：）

Answer 2

我想我明白了，请告诉我是否有更好的方法：

[[Model]]
    (Model(gaussian_cdf, prefix='g1_') + Model(gaussian_cdf, prefix='g2_'))
[[Fit Statistics]]
    # fitting method   = leastsq
    # function evals   = 66
    # data points      = 50
    # variables        = 6
    chi-square         = 0.00626332
    reduced chi-square = 1.4235e-04
    Akaike info crit   = -437.253376
    Bayesian info crit = -425.781238
[[Variables]]
    g1_amp:    0.65818908 +/- 0.00851338 (1.29%) (init = 0.5)
    g1_mu:     93.8438526 +/- 0.01623273 (0.02%) (init = 94)
    g1_sigma:  0.54362156 +/- 0.02021614 (3.72%) (init = 1)
    g2_amp:    0.34058664 +/- 0.01153346 (3.39%) (init = 0.5)
    g2_mu:     97.7056728 +/- 0.06408910 (0.07%) (init = 98)
    g2_sigma:  1.24891832 +/- 0.09204020 (7.37%) (init = 1)
[[Correlations]] (unreported correlations are < 0.100)
    C(g1_amp, g2_amp)     = -0.892
    C(g2_amp, g2_sigma)   =  0.848
    C(g1_amp, g2_sigma)   = -0.744
    C(g1_amp, g1_mu)      =  0.692
    C(g1_amp, g2_mu)      =  0.662
    C(g1_mu, g2_amp)      = -0.607
    C(g1_amp, g1_sigma)   =  0.571

使用Android中的Pattern从标准文本中获取一些字符串

2 个答案: