Question

我想选择具有条件但不起作用的数据库。

我有这个问题：

 SELECT c.*
      ,s.*
      ,f.*
      ,count(c.id) as instock_count
      ,totals.orders_total
      ,GROUP_CONCAT(c.sku SEPARATOR '<br/>') AS sku
  FROM produse_com c
    INNER JOIN (SELECT * , SUM(stoc) as stoc_sum
                FROM stocuri_mentor 
                GROUP BY sku ) s 
      ON c.sku = s.sku
  INNER JOIN (SELECT count(id) as orders_total, id_comanda 
               FROM produse_com 
               WHERE NOT ridicat = 'Da'
                GROUP BY id_comanda ) totals
     ON totals.id_comanda = c.id_comanda 
  INNER JOIN (SELECT data_add, status, id_comanda
                FROM comenzi 
                  WHERE NOT (status = 'Impachetat' OR status = 'Stornat' OR status = 'Anulat')
                  ) f
     ON f.id_comanda = c.id_comanda
  WHERE stoc_sum >= c.qty
  GROUP BY c.id_comanda
  HAVING instock_count = orders_total

问题是我有条件WHERE NOT ridicat = 'Da'
但结果包含ridicat = 'Da'

的所有结果

编辑： 如果我删除此查询INNER JOIN (SELECT * ,SUM(stoc) as stoc_sum FROM stocuri_mentor GROUP BY sku ) s ON c.nume_produs = s.sku和WHERE stoc_sum >= c.qty，结果就可以了

编辑2：解决方案=再添加一个条件WHERE stoc_sum >= c.qty AND ridicat <> 'Da'

Answer 1

您可以尝试此查询。

 SELECT count(id) as orders_total, id_comanda,  ridicat
                   FROM produse_com 
                   WHERE ridicat != 'Da'
                    GROUP BY id_comanda;

选择INNER JOIN mysql DataBase

1 个答案: