MySQL选择帮助内连接？

Question

我正在编写一个php脚本，显示以下列project_name，customer_name，fName，lName，activeproject。这是我的高级项目的网站的一部分，我真的需要帮助。

我的表格设置如下： 的项目 project_id，project_name，description，custid，projectmgrempid，activeproject

员工 staff_id，fName，lName

客户 cust_id，cust_fname

这就是我所拥有的错误

select t1.project_id, t1.project_name, t1.description, 
t1.custid, t1.projectmgrempid, t1.activeproject, t2.fName, t2.lName, t3.customer_id,    t3.customer_name
from projects t1
inner join employee t2 on t1.projectmgrempid = t2.staff_id
where t1.activeproject = `open`
inner join customer t3 on t1.custid = t3.customer_id;

  

错误是＃1064 - 您的SQL语法出错;检查   手册，对应右边的MySQL服务器版本   在t1.custid =上使用near＆t;内连接客户t3的语法   t3.customer_id LIMIT 0,30＆＃39;在第6行

Answer 1

您的where子句应出现在您的join子句之后。

select t1.project_id, t1.project_name, t1.description, 
t1.custid, t1.projectmgrempid, t1.activeproject, 
t2.fName, t2.lName, t3.customer_id,    t3.customer_name
from projects t1
inner join employee t2 on t1.projectmgrempid = t2.staff_id
inner join customer t3 on t1.custid = t3.customer_id
where t1.activeproject = 'open';