Question

如果两个相邻的名称相同但不是数字，则打印出相应的消息，但仍打印出第二个条目的数据。如果两个相邻的条目相同（名称和编号），则打印出重复的错误消息（如前面的类中所示）。跟踪处理的条目数。

我需要帮助实现上述内容。我有PhoneNumber以及Name类。以下是我的代码：

private Name name;
private PhoneNumber phonenumber;    

public PhonebookEntry(Name name, PhoneNumber phonenumber) {
    this.name = name;
    this.phonenumber = phonenumber; 
}

public void call() {
    System.out.println("Dialing "+ name.getFormal()+ ": ("+phonenumber.getAreaCode() +")"
    + phonenumber.getExchange()+"-" + phonenumber.getLineNumber());
    System.out.println();
}


public static void main(String[] args) throws FileNotFoundException {
    File myFile = new File("phonebook.text"); 
    Scanner scanner = new Scanner(myFile);

    int count =0;

    while(scanner.hasNext()) {
         Name name = new Name(scanner.next(), scanner.next());
         PhoneNumber phonenumber = new PhoneNumber(scanner.next());
         PhonebookEntry entry = new PhonebookEntry(name,phonenumber);
         count++;
         System.out.println( "phone book entry: "+name + ": "+ phonenumber);

        entry.call();
    }

    System.out.println( count+" phonebook entries processed.");
}

这就是我迄今所拥有的。

Answer 1

为您的所有实体实施equals（） - Name，PhoneNumber，PhonebookEntry。 https://www.geeksforgeeks.org/overriding-equals-method-in-java/

跟踪之前的PhonebookEntry：例如，

PhonbookEntry prevEntry = null;
while(scanner.hasNext()) {
    Name name = new Name(scanner.next(), scanner.next());
    PhoneNumber phonenumber = new PhoneNumber(scanner.next());
    PhonebookEntry entry = new PhonebookEntry(name,phonenumber);
    if(prevEntry != null){
        if(prevEntry.equals(entry)) // Exact same entry
            //print out error message
        else if(prevEntry.name.equals(entry.name) && !prevEntry.phoneNumber.equals(entry.phoneNumber))
            // print out the data
    }
    count++;
    System.out.println( "phone book entry: "+name + ": "+ phonenumber);}
    prevEntry = entry;

}

希望这有帮助

在以下程序（OOP）中实现某些功能

1 个答案: