Question

我正在尝试使用以下for循环和x = 1来实现以下系列，但是没有得到所需的结果，有人可以指定我出错的地方吗？

我附上了该系列的图片如下：

var valKeyDown;
var valKeyUp;


function integerOnly(e) {
    e = e || window.event;
    var code = e.which || e.keyCode;
    if (!e.ctrlKey) {
        var arrIntCodes1 = new Array(96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 8, 9, 116);   // 96 TO 105 - 0 TO 9 (Numpad)
        if (!e.shiftKey) {                          //48 to 57 - 0 to 9 
            arrIntCodes1.push(48);                  //These keys will be allowed only if shift key is NOT pressed
            arrIntCodes1.push(49);                  //Because, with shift key (48 to 57) events will print chars like @,#,$,%,^, etc.
            arrIntCodes1.push(50);
            arrIntCodes1.push(51);
            arrIntCodes1.push(52);
            arrIntCodes1.push(53);
            arrIntCodes1.push(54);
            arrIntCodes1.push(55);
            arrIntCodes1.push(56);
            arrIntCodes1.push(57);
        }
        var arrIntCodes2 = new Array(35, 36, 37, 38, 39, 40, 46);
        if ($.inArray(e.keyCode, arrIntCodes2) != -1) {
            arrIntCodes1.push(e.keyCode);
        }
        if ($.inArray(code, arrIntCodes1) == -1) {
            return false;
        }
    }
    return true;
}

$('.integerOnly').keydown(function (event) {
    valKeyDown = this.value;
    return integerOnly(event);
});

$('.integerOnly').keyup(function (event) {          //This is to protect if user copy-pastes some character value ,..
    valKeyUp = this.value;                          //In that case, pasted text is replaced with old value,
    if (!new RegExp('^[0-9]*$').test(valKeyUp)) {   //which is stored in 'valKeyDown' at keydown event.
        $(this).val(valKeyDown);                    //It is not possible to check this inside 'integerOnly' function as,
    }                                               //one cannot get the text printed by keydown event 
});                                                 //(that's why, this is checked on keyup)

$('.integerOnly').bind('input propertychange', function(e) {    //if user copy-pastes some character value using mouse
    valKeyUp = this.value;
    if (!new RegExp('^[0-9]*$').test(valKeyUp)) {
        $(this).val(valKeyDown);
    }
});

出于某种原因，我得到的结果完全不同，因为我的数字是负数，但我已经重新查看了我的代码，但我仍然不确定它的来源。

由于

Answer 1

您的索引已经完成。在你提出的cumsum陈述开头

x.^(2*(k-1)-1)

应该是哪个。。

x.^(2*(k-1)+1)

实施以下系列？

1 个答案: