我试图通过识别存储为SMALLINT的userID和存储为BINARY(32)的passwordTest来选择表中的所有数据。这是我用来制作表格的查询:
{ {CREATE TABLE IF NOT EXISTS `test`.`User`
(`UserID` SMALLINT UNSIGNED ZEROFILL NOT NULL AUTO_INCREMENT,
`firstname` VARCHAR(35) NOT NULL,
`lastname` VARCHAR(35) NOT NULL,
`passwordTest` BINARY(32) NOT NULL,
`registration_date` DATETIME DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`UserID`),
UNIQUE INDEX `password_UNIQUE` (`passwordTest` ASC));}
以下是我用于将测试值插入表中的查询:
{INSERT INTO USER (firstname, lastname, passwordTest)
VALUES('Test','1','password');}
这是我的SQL查询,它不起作用:
{USE test;
SELECT * FROM USER WHERE userID = '00001' AND passwordTest = 'password';}
非常感谢任何帮助
答案 0 :(得分:0)
因为您将密码列定义为二进制,所以您必须在where子句中将密码转换为二进制。这适用于mysql5.6
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