Question

我现在正在tkinter制作摇滚，纸张，剪刀射击游戏，我正在尝试编写一个决定谁获胜的功能。 1 =岩石，2 =纸，3 =剪刀。除了comp == 2和choice == 1。

之外，脚本不会打印任何内容

requiredAssemblies.Keys

Answer 1

我认为你走错了方向。假设我们必须使用数字输入，我会这样做：

ROCK, PAPER, SCISSORS = range(1, 4)

roshambo = {
    ROCK: SCISSORS,
    PAPER: ROCK,
    SCISSORS: PAPER
}

def Winning(comp, choice):
    if comp == choice:
        messagebox.showinfo("Info", "DRAW!!!")
    elif comp == roshambo[choice]:
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "YOU LOSE!!!")

这使您的逻辑清晰并简化了代码。并且，它可以更容易地扩展问题：

ROCK, PAPER, SCISSORS, LIZARD, SPOCK = range(1, 6)

roshambo = {
    ROCK: [LIZARD, SCISSORS],
    PAPER: [ROCK, SPOCK],
    SCISSORS: [PAPER, LIZARD],
    LIZARD: [SPOCK, PAPER],
    SPOCK: [SCISSORS, ROCK]
}

def Winning(comp, choice):
    if comp == choice:
        messagebox.showinfo("Info", "DRAW!!!")
    elif comp in roshambo[choice]:
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "YOU LOSE!!!")

字典是你的朋友，没有它们就不会编程！

Answer 2

你在哪里获得comp和choice？

这样的事情会起作用：

from tkinter import messagebox

rock=1
paper=2
scissors=3


def Winning(comp, choice):
    if (((comp == 2) and (choice == 1)) or ((comp == 3) and (choice == 2)) or((comp == 1) and (choice == 3))):
        messagebox.showinfo("Info", "YOU LOSE!!!")
    if (((choice == 2) and (comp == 1)) or ((choice == 3) and (comp == 2)) or((choice == 1) and (comp == 3))):
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "DRAW!!!")


Winning(rock, paper)

这是你想要的吗？

python（和，或）中逻辑语句的组合

2 个答案: