Question

我想问一下如何在派生类重写函数中调用隐藏的Base类操作符函数，下面是我的代码，注释行是问题。

class Base{
public:
    virtual bool operator^(Base &b){
        cout << "hehe" << endl;
        return true;
    }
    virtual void fn() = 0;
};

class Dev: public Base{
public:
    virtual bool operator^(Base &b){
        // how to call operator ^ in the Base class here??
        cout << "haha" << endl;
        return false;
    }
    virtual void fn(){}
};

Answer 1

使用运营商的限定名称。

例如

#include <iostream>

using namespace std;

class Base{
public:
    virtual bool operator^(Base &b){
        cout << "hehe" << endl;
        return true;
    }
    virtual void fn() = 0;
};

class Dev: public Base{
public:
    virtual bool operator^(Base &b){
        Base::operator^( b );
        cout << "haha" << endl;
        return false;
    }
    virtual void fn(){}
};

int main() 
{
    Dev v;
    Base &b = v;

    v ^ b;

    return 0;
}

程序输出

hehe
haha

Answer 2

You can also do an explicit upcast of *this:

class Dev: public Base{
public:
    virtual bool operator^(Base &b)
    {
        static_cast<Base&>(*this) ^ b;

        cout << "haha" << endl;
        return false;
    }
    virtual void fn(){}
};

调用c ++隐藏的运算符函数

2 个答案: