Question

Scanner s = new Scanner(System.in);
System.out.println("Type a number");
int n = s.nextInt();
int start = 0;
int largest = 0;
int occurrence = 0;

while(n > start){
    int number = (int)(Math.random()*100);
    if(number > largest){
        largest = number;


    }
    n--;
    System.out.print(number+" ");
}

System.out.println("max is "+largest);
System.out.println("Occurrence is "+occurrence);

我希望能够找到最大的int的出现，我不知道如何以一种相当简单的方式这样做。我尝试在occurrence++;下添加largest = number;，但这不起作用。

例如，我输入6作为输入，我会得到随机数54, 74, 61, 89, 13, 89。所需的输出为max is 89. Occurrence is 2.

另外，我试图只让代码每行只打印10个数字，然后它会跳到下一行并继续。

Answer 1

如果再次发生，请增加发生变量;
在新的较大数字

1

您可以使用

if(number > largest){
    largest = number; // found larger value
    occurrence = 1; // reset occurrence back to initial 
}else if(number == largest){
     occurrence++; // keep track of same large value
}

Answer 2

您需要使用else if条件来检查这样的相等

Scanner s = new Scanner(System.in);
    System.out.println("Type a number");
    int n = s.nextInt();
    int start = 0;
    int largest = 0;
    int occurrence = 1;

    while(n > start){
        int number = (int)(Math.random()*100);
        if(number > largest){
            largest = number;


        }else if(number == largest){
            occurrence++;
        }
        n--;
        System.out.print(number+" ");
    }

    System.out.println("max is "+largest);
    System.out.println("Occurrence is "+occurrence);

P.S - 初始化occurrence = 1，因为至少有一次会出现最大数字

Answer 3

我想你差不多了。基本上，您错过了检查新随机数是否等于当前最大数字。类似的东西：

library(tidyr)
df %>% spread(b, c)

另外，请记住在找到新的最大号码时重置发生次数：

if (number == largest) {
    occurrences++;
}

如何在一组随机数中找到最大数字

3 个答案: