booking No Movie Name Guest Name
---------------------------------------------
643042 Horrer Movie MARLON HARRIS
643042 Horrer Movie ALICE HARRIS
我想在SQL Server
中显示如下记录643042 Horrer Movie ALICE HARRIS / MARLON HARRIS
答案 0 :(得分:0)
尝试这样的事情:
ArrayList
答案 1 :(得分:0)
如评论中所述,使用FOR XML PATH
;WITH T ([booking No] , [Movie Name] , [GuestName])
AS
(
SELECT 643042 , 'Horrer Movie', 'MARLON HARRIS'
UNION ALL
SELECT 643042 , 'Horrer Movie', 'ALICE HARRIS'
)
SELECT [booking No] , [Movie Name] ,
GuestNames = LTRIM(RTRIM(STUFF(CAST((SELECT ' / '+ B.[GuestName]
FROM T B
WHERE a.[booking No] = b.[booking No]
FOR XML PATH (''),TYPE) AS NVARCHAR(1000)),1,2,'')))
FROM T A
GROUP BY [booking No] , [Movie Name]