连接一列SQL的行

Question

我正在使用以下查询来提取约会数据：

SELECT app.subject, AL.locationName
FROM FilteredAppointment app
INNER JOIN appointmentlocation AL ON app.activityid = AL.appointment
WHERE app.scheduledstart='2013-07-06 15:00:00.000'

输出如下，有2行（具有两个不同位置的相同约会）：

如何修改此查询以仅显示一行，其中两个位置与逗号连接，如下所示：

Column1:（MZN; OTV）* ...
Column2: Room1，Room2

由于

Answer 1

你需要的是SQL Join and concatenate rows，关于它的问题有很多问题。 在SQL Server中没有简单的方法，但这里有一些技巧：

使用 select for xml

连接

select
    app.subject,
    stuff(
       (
           select ', ' + AL.locationName
           from appointmentlocation as AL
           where AL.appointment = app.activityid
           for xml path(''), type
       ).value('.', 'nvarchar(max)')
    , 1, 2, '') 
from FilteredAppointment as app
where app.scheduledstart='2013-07-06 15:00:00.000'

如果您只有一条来自FilteredAppointment的记录要连接，您可以使用汇总到变量：

declare @locations nvarchar(max), @activityid int

select @activityid = ???

select @locations = isnull(@locations + ', ', '') + AL.locationName
from appointmentlocation as AL
where AL.appointment = @activityid

print @locations

Answer 2

这个例子可以帮助你......或者等到我为你查询

  USE app.subject,
    SELECT      AL.locationName AS [Loc],
                STUFF((    SELECT ',' + SUB.Name AS [text()]
                            – Add a comma (,) before each value
                            FROM appointmentlocation AL
                            WHERE
                            app.activityid = AL.appointment

                            FOR XML PATH('') – Select it as XML
                            ), 1, 1, '' )
                            – This is done to remove the first character (,)
                            – from the result
                AS [Sub Categories]
    FROM  FilteredAppointment app

Answer 3

SELECT app.subject, GROUP_CONCAT(AL.locationName, ', ') AS LocationName
FROM FilteredAppointment app
INNER JOIN appointmentlocation AL ON app.activityid = AL.appointment
WHERE app.scheduledstart='2013-07-06 15:00:00.000'
GROUP BY app.subject

未测试

Answer 4

我现在无法测试它，但我认为这可能会起作用

select subject, 
       group_concat(name separator ',') Newcolumn
  from table
 group by subject