Question

我想创建像这样的json字符串 -

{
    "credentials": {
        "name":"abc",
        "password":"pass"
    }
}

我创建了一个名为Credentials的Java类，其中包含“name”和“password”字段。我在凭证对象中添加了名称和密码值。为了给出一个REST调用，我想在body部分发送json对象/字符串，如前所述。但我的Json字符串/对象在json字符串中没有凭据名称。它看起来像这样 -

{
    "name": "jamal11",
    "password": "5test5@5"
}

下面是我将Credentials对象转换为JSON字符串的代码 -

credentials.setName(name);
credentials.setPassword(password);

//conversion of RequestParamDto object to JSON 
ObjectWriter ow = new ObjectMapper().writer().withDefaultPrettyPrinter();
String requestParamJson = ow.writeValueAsString(credentials);

//add requestParam string to HttpPost
httpPost.setEntity(new StringEntity(requestParamJson, "UTF-8"));

我在这里遗漏了什么吗？请帮帮我。谢谢！

Answer 1

你应该让一个json对象放置一个参数，其中参数的键是“凭证”，参数的值是一个json数组，它是一个json对象。或创建一个类，该类具有凭证对象作为标签在json中显示的属性

{
    "credentials": [{
        "name":"abc",
        "password":"pass"
    }]
}

示例：

class MyInterfaceList {
    @JsonProperty("credentials")
    private List<MyInterface> list;

    public List<MyInterface> getList() {
        return list;
    }

    public void setList(List<MyInterface> list) {
        this.list = list;
    }
}

final List<MyInterface> lists = new ArrayList<MyInterface>(4);
lists.add(new MyImpl("abc", "pass"));
MyInterfaceList listHolder = new MyInterfaceList();
listHolder.setList(lists);
final String json = mapper.writeValueAsString(listHolder);

Object Writer 这是更好的选择。使用已配置的ObjectWriter实例生成JSON。特别是，我们对withRootName方法感兴趣：

final List<MyInterface> lists = new ArrayList<MyInterface>(4);
lists.add(new MyImpl("abc", "pass"));
final ObjectWriter writer = mapper.writer().withRootName("credentials");
final String json = writer.writeValueAsString(lists);

Answer 2

记得将json jar文件添加到项目库中

JSONObject a = new JSONObject();
a.accumulate("credentials", new JSONObject().put("name", "abc").put("password", "123"));

json字符串中缺少对象名称

2 个答案: