Question

编写一个程序来模拟抛硬币。首先，要求用户打电话＆＃34;或者预测折腾。接下来，让用户知道你在掷硬币。然后报告用户是否正确。

示例：
 Please call the coin toss (h or t): h

  Tossing...

 The coin came up heads. You win!

这是关于我应该做的事情。这是我到目前为止的代码：

package inClassCh4Sec8to9;

import java.util.Random;
import java.util.Scanner;

public class ClassCh4Sec8to9 {

  public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    while (true) {
        System.out.print("Enter you guess (1 for heads, 0 for tails, 2 to quit):");
        int call = input.nextInt();
        int heads = 1;
        int quit = 2;
        int tails = 0;

        if (call == quit) {
            break;
        } else if (call == heads) {

        } else if (call == tails) {

        } else {
            System.out.println("invalid");
            continue;
        }
        Random random = new Random();
        int coinflip = random.nextInt(2);
        if(call == coinflip){
            System.out.println("Correct!");
        }else{
            System.out.println("Sorry, incorrect.");
        }

    }
  }
}

我的问题：

我可以得到一个随机数没问题，但它允许h和t用作1和0。
我希望h或者头等于1作为输入。

Answer 1

而不是Random.nextInt()，我更喜欢nextBoolean()。不要在循环中重新声明你的Random。如果输入以h开头，则guess设置为true;否则，请确保它有效（并将其设置为false）。然后翻转coin，并比较结果。像，

Scanner input = new Scanner(System.in);
Random random = new Random();

while (true) {
    System.out.print("Please call the coin toss (h or t): ");
    String call = input.nextLine().toLowerCase();
    boolean guess = call.startsWith("h"), coin = random.nextBoolean();
    if (call.startsWith("q")) {
        break;
    } else if (!guess && !call.startsWith("t")) {
        System.out.println("invalid");
        continue;
    }
    if ((guess && coin) || (!guess && !coin)) {
        System.out.printf("The coin came up %s. You win!%n", coin ? "heads" : "tails");
    } else {
        System.out.printf("The coin came up %s. You lose!%n", coin ? "heads" : "tails");
    }
}

Answer 2

pd.date_range

硬币使用用户输入折腾JavaScript

2 个答案: