Python Coin Toss

Question

我对Python非常陌生，我必须创建一个模拟翻转硬币的游戏，并要求用户输入掷硬币的次数。基于该响应，程序必须选择0或1的随机数（并且决定哪个代表“头”并且代表“尾部”）指定的次数。计算“头部”的数量和产生的“尾部”的数量，并向用户呈现以下信息：由模拟的硬币投掷组成的列表，以及头部数量和产生的尾部数量的摘要。例如，如果用户输入5，则掷硬币模拟可能会导致['head'，'tails'，'tails'，'head'，'heads']。该程序应该打印如下内容：“['head'，'tails'，'tails'，'head'，'heads']

这是我到目前为止所做的，而且根本不起作用......

import random

def coinToss():
    number = input("Number of times to flip coin: ")
    recordList = []
    heads = 0
    tails = 0
    flip = random.randint(0, 1)
    if (flip == 0):
        print("Heads")
        recordList.append("Heads")
    else:
        print("Tails")
        recordList.append("Tails")
    print(str(recordList))
    print(str(recordList.count("Heads")) + str(recordList.count("Tails")))

Answer 1

您需要loop才能执行此操作。我建议使用for循环：

import random
def coinToss():
    number = input("Number of times to flip coin: ")
    recordList = []
    heads = 0
    tails = 0
    for amount in range(number):
         flip = random.randint(0, 1)
         if (flip == 0):
              print("Heads")
              recordList.append("Heads")
         else:
              print("Tails")
              recordList.append("Tails")
    print(str(recordList))
    print(str(recordList.count("Heads")) + str(recordList.count("Tails")))

我建议你阅读this on for loops。

此外，您可以将number作为parameter to the function传递：

import random
def coinToss(number):
    recordList, heads, tails = [], 0, 0 # multiple assignment
    for i in range(number): # do this 'number' amount of times
         flip = random.randint(0, 1)
         if (flip == 0):
              print("Heads")
              recordList.append("Heads")
         else:
              print("Tails")
              recordList.append("Tails")
    print(str(recordList))
    print(str(recordList.count("Heads")) + str(recordList.count("Tails")))

然后，您需要在最后调用该函数：coinToss()。

Answer 2

你快到了：

1）你需要调用函数：

coinToss()

2）您需要设置一个循环来重复调用random.randint()。

Answer 3

我会采取以下方式：

from random import randint
num = input('Number of times to flip coin: ')
flips = [randint(0,1) for r in range(num)]
results = []
for object in flips:
        if object == 0:
            results.append('Heads')
        elif object == 1:
            results.append('Tails')
print results

Answer 4

这可能更加pythonic，虽然不是每个人都喜欢列表理解。

import random

def tossCoin(numFlips):      
    flips= ['Heads' if x==1 else 'Tails' for x in [random.randint(0,1) for x in range(numflips)]]
    heads=sum([x=='Heads' for x in flips])
    tails=numFlips-heads

Answer 5

import random
import time



flips = 0
heads = "Heads"
tails = "Tails"

heads_and_tails = [(heads),
                   (tails)]
while input("Do you want to coin flip? [y|n]") == 'y':
    print(random.choice(heads_and_tails))
    time.sleep(.5)
    flips += 1


else:
    print("You flipped the coin",flips,"times")
    print("Good bye")

你可以尝试这个，我有它所以它会问你是否要翻转硬币然后当你说不，或者它告诉你你翻了几次硬币。 （这是在python 3.5中）

Answer 6

创建一个包含两个元素的列表，该元素包含头和尾，并使用random中的choice（）获得硬币翻转结果。要获得头或尾出现的次数的计数，请将计数附加到列表中，然后使用集合中的Counter（list_name）。使用uin（）调用

##coin flip
import random
import collections
def tos():
    a=['head','tail']
    return(random.choice(a))
def uin():
    y=[]
    x=input("how many times you want to flip the coin: ")
    for i in range(int(x)):
        y.append(tos())
    print(collections.Counter(y))

Answer 7

除了这些，您还可以这样做：

import random
options = ['Heads' , 'Tails']
number = int(input('no.of times to flip a coin : ')
for amount in range(number):
   heads_or_tails = random.choice(options)
   print(f" it's {heads_or_tails}")
print()
print('end')

Answer 8

我就是这样做的。可能不是最好和最有效的方式，但嘿，现在您有不同的选择可供选择。我循环了 10000 次，因为练习中已经说明了这一点。

#Coinflip program
import random

numberOfStreaks = 0
emptyArray = []
for experimentNumber in range(100):
#Code here that creates a list of 100 heads or tails values
headsCount = 0
tailsCount = 0
#print(experimentNumber)
for i in range(100):
    if random.randint(0, 1) == 0:
        emptyArray.append('H')
        headsCount +=1
    else:
        emptyArray.append('T')
        tailsCount += 1   

#Code here that checks if the list contains a streak of either heads or tails of 6 in a row
heads = 0
tails = 0
headsStreakOfSix = 0
tailsStreakofSix = 0

for i in emptyArray:
    if i == 'H':
        heads +=1
        tails = 0
        if heads == 6:
            headsStreakOfSix += 1
            numberOfStreaks +=1
            
    if i == 'T':
        tails +=1
        heads = 0
        if tails == 6:
            tailsStreakofSix += 1
            numberOfStreaks +=1
            
#print('\n' + str(headsStreakOfSix))
#print('\n' + str(tailsStreakofSix))
#print('\n' + str(numberOfStreaks))
print('\nChance of streak: %s%%' % (numberOfStreaks / 10000))

Answer 9

#program to toss the coin as per user wish and count number of heads and tails
import random
toss=int(input("Enter number of times you want to toss the coin"))
tail=0
head=0
for i in range(toss):
    val=random.randint(0,1)
    if(val==0):
        print("Tails")
        tail=tail+1
    else:
        print("Heads")
        head=head+1
print("The total number of tails is {} and head is {} while tossing the coin {} times".format(tail,head,toss))
    

Answer 10

import random

def coinToss(number):
    heads = 0
    tails = 0
    for flip in range(number):
        coinFlip = random.choice([1, 2])

        if coinFlip == 1:
            print("Heads")
            recordList.append("Heads")
        else:
            print("Tails")
            recordList.append("Tails")

number = input("Number of times to flip coin: ")
recordList = []
if type(number) == str and len(number)>0:
    coinToss(int(number))
    print("Heads:", str(recordList.count("Heads")) , "Tails:",str(recordList.count("Tails")))