Question

我有两个列表如下：

List("key1", "key2")
List("val1", "val2")

我试图让它变成类似JSON的格式：

[{"key1":"val1"},{"key2","val2"}]

现在，这就是我正在使用的：

val output = List(attrKeys.zip(attrValues).toMap)

但它给了我这个：

[{"key1":"val1","key2":"val2"}]

如何将其添加到单独的地图对象列表中？

Answer 1

import matplotlib.pyplot as plt
import numpy as np

def generateData(goal):
    x=[_ for _ in range(20)]
    y=[10+np.random.exponential()*5 for _ in range(100)]
    return x,y

def drawHistogram(data,nBins):
    plt.figure()
    plt.hist(diffs,nBins)

sweep=np.linspace(10,20,4)

for goal in sweep:
    for gw2 in sweep:

        diffs=[]

        for i in range(10):
            data=generateData(goal)
            diffs.append(goal-np.mean(data[1]))

        #generate plot
        plt.figure(1)
        clr=(abs(np.mean(diffs))/goal,0,0)
        plt.plot([goal], [gw2], marker="s", mew='1', ms='35', color=clr)

        drawHistogram(diffs,5) ##Comment this line out to see what the final graph should look like

plt.draw()
plt.show()

Scala：将两个列表压缩成json数组格式

1 个答案: