Question

下表'mydata'有四列payId，custId，rScore，bScore

payId   custId  rScore  bScore

A        1         0.2       0
A        2         0.3       1
A        4         0.65      1
A        1         0.35      0
B        3         0.5       1
B        5         0.3       1
B        5         0.85      0

将rScore定义为： a）rScore <0.5然后'<0.5'， b）rScore＆gt; = 0.5然后'＆gt; = 0.5'

查找

根据每个payId和范围计算不同的custId。
根据每个payId和范围计算比率（总数1）/（总数1和0）

我想从SQL查询

payId   range  custId  ratio
A        <0.5   2        0.33  
A        >=0.5  1        1
B        <0.5   1        1
B        >=0.5  2        0.5

这是我尝试的但是我没有得到所需的输出 -

SELECT payId, IF(rscore< 0.5, '<0.5','>=0.5') As range, 
Case 
    When rscore< 0.5 then Count(Distict(custId))
    When rscore >=0.5 then Count(Distict(custId)))
End AS custID
From mydata

Answer 1

您需要将数据分组到第一列，因为您不希望输出中的所有行。如果您使用的是MSSQL，这应该可以使用。

; WITH cte_range AS (
    SELECT
        *
        ,CASE WHEN rScore < 0.5 THEN '<0.5' ELSE '>=0.5' END AS range
    FROM
        mydata
)
SELECT
    payId
    ,range
    ,COUNT(DISTINCT custId) as distinctCustomers
    ,AVG(bScore) AS ratio
FROM 
    cte_range
GROUP BY
    payId
    ,range
ORDER BY
    payId
    ,range;

Answer 2

您还需要在该计算范围内使用GROUP BY 一种方法是在GROUP BY中重复计算时的情况

SELECT 
 payId, 
 (CASE WHEN rscore < 0.5 THEN '<0.5' WHEN rscore >= 0.5 THEN '>=0.5' END) AS range, 
 COUNT(DISTINCT custId) AS TotalCustId,
 AVG(ratio) AS AverageRatio
FROM mydata
GROUP BY 
 payId, 
 (CASE WHEN rscore < 0.5 THEN '<0.5' WHEN rscore >= 0.5 THEN '>=0.5' END)
ORDER BY 1, 2;

或者使用子查询和组

SELECT payId, range, 
  COUNT(DISTINCT custId) AS TotalCustId, 
  AVG(ratio) AS AverageRatio
FROM (
    SELECT payId, custId, ratio,
    (CASE
     WHEN rscore < 0.5 THEN '<0.5'
     WHEN rscore >= 0.5 THEN '>=0.5'
     END) AS range
    FROM mydata
) AS Q
GROUP BY payId, range
ORDER BY payId, range;

Answer 3

MSSQL解决方案

with cte as (
  select *,range=iif(rscore< 0.5, '<0.5','>=0.5') from t
) 
  select payid,range,cnt_custid=count(distinct (custid)),
    ratio=avg(bScore) from cte
  group by payid,range
  ORDER BY payId, range;

如何从SQL查询中获取自定义值

查找

我想从SQL查询

3 个答案: