如何在laravel中获取列名列的值

Question

表（技能）

有许多技能，列类型为boolean（0,1），由laravel提供  如果技能值等于1且user_id等于1，我想获取列的名称， 没有说列的名称因为他们50技能，我在崇高

尝试了这个

<?php
$variable2=App\Skill::where('user_id',Auth::user()->id)
       ->where('job_id','null')
       ->get();
?>


@foreach($variable2 as $key1 => $value1)

      @if($value1='1')
          <span class="tags">{{ $key1 }}</span>
      @endif 
@endforeach

Answer 1

好吧，看起来你忘记了，<?php $userSkills = App\Skill::where('user_id',Auth::user()->id) ->where('job_id','null') ->get(); ?> <!-- loop through a list of user skills (get gives us a set of skills --> @foreach($userSkills as $skill) <!-- loop through skill properties --> @foreach($skill->toArray() as $key => $value) @if($value) <span class="tags">{{ $key }}</span> @endif @endforeach @endforeach 返回了一系列技能。你必须使用两个循环。

yaml

Answer 2

<?php    $variable2=App\Skill::where('user_id',Auth::user()->id)
           ->where('job_id','null')
           ->where('user_id', 1)
           ->get();

    $skills = $variable2->filter(function ($item) { return $item === 1; })->keys();
?>

    @foreach($skills as $key)
    <span class="tags">{{ $key }}</span>
    @endforeach