在关系数据库中按名称获取值

Question

在资源文件中使用此代码

@forelse($teachers as $teacher)
    {{$teacher->name}} {{$teacher->subjects}}<br>
    @empty
    Nothing
    @endforelse

获得此值

helooo [{"id":3,"name":"Hindi","created_at":"2017-11-18 12:43:33","updated_at":"2017-11-18 12:43:33","pivot":{"teacher_id":16,"subject_id":3}}]
malik [{"id":2,"name":"English","created_at":"2017-11-18 12:43:12","updated_at":"2017-11-18 12:43:12","pivot":{"teacher_id":17,"subject_id":2}}]
hello [{"id":1,"name":"Maths","created_at":"2017-11-18 12:42:34","updated_at":"2017-11-18 12:42:34","pivot":{"teacher_id":18,"subject_id":1}}]

但是使用了

 {{$teacher->name}} {{$teacher->subjects->name}}

收到错误

Property [name] does not exist on this collection instance

如何才能获得laravel中的名称值

Answer 1

由于它有很多，所以你需要迭代每位老师的主题：

@forelse($teachers as $teacher)
    {{ $teacher->name }}<br>
    @foreach ($teacher->subjects as $subject)
        {{ $subject->name }}<br>
    @endforeach
@empty
    Nothing
@endforelse

Answer 2

看起来返回的数据是数组中的对象。尝试添加零以选择此arr中的第一个obj。像这样：

$teacher->subjects[0]->name

祝你好运！