我想在事务中拥有一堆插件,以便在出现任何错误时可以回滚。现在我的问题是,对于某些插入,我需要前一个插入的ID。但是,执行var id = (int)command.ExecuteScalar();
会抛出异常("对象引用未设置为对象的实例")。如果我在不尝试分配结果的情况下运行command.ExecuteScalar()
,则代码可以正常工作。在提交交易之前是否可以获得ID?如果不是,我的替代方案是什么?
我的代码:
using (SqlConnection connection = new SqlConnection("ConnectionHere")
{
connection.Open();
SqlCommand command = connection.CreateCommand();
SqlTransaction transaction;
// Start a local transaction.
transaction = connection.BeginTransaction();
command.Connection = connection;
command.Transaction = transaction;
try
{
string insertStudent = "INSERT INTO Students (FirstName, MiddleName, LastName)" +
" VALUES (@firstName, @middleName, @lastName)";
command.CommandText = insertStudent;
command.Parameters.AddWithValue("@firstName", application.FirstName);
command.Parameters.AddWithValue("@middleName", application.MiddleName);
command.Parameters.AddWithValue("@lastName", application.LastName);
var id = (int) command.ExecuteScalar();//EXCEPTION THROWN HERE
// Attempt to commit the transaction.
transaction.Commit();
}
catch (Exception ex)
{
Console.WriteLine("Commit Exception Type: {0}", ex.GetType());
Console.WriteLine(" Message: {0}", ex.Message);
// Attempt to roll back the transaction.
transaction.Rollback();
}
}
答案 0 :(得分:1)
我假设Students表中的一列被设置为标识列,并且您使用的是SQL Server 2008 +。
在这种情况下,您需要更改SQL语句以返回插入的标识值,如下所示:
string insertStudent = "INSERT INTO Students (FirstName, MiddleName, LastName)" +
" VALUES (@firstName, @middleName, @lastName);" +
" SELECT SCOPE_IDENTITY();";
有关SCOPE_IDENTITY的更多信息,请访问:https://docs.microsoft.com/en-us/sql/t-sql/functions/scope-identity-transact-sql
答案 1 :(得分:0)
使用此SQL语法获取插入的ID:
INSERT INTO Students (FirstName, MiddleName, LastName) OUTPUT Inserted.ID ....
然后
int id = command.ExecuteScalar();
答案 2 :(得分:0)
只需更改代码
即可 var id = (int) command.ExecuteScalar();
为:
int id = Convert.ToInt32(cmd.ExecuteScalar());
这将确保即使ExecuteScalar返回null,由于未在存储过程中选择任何内容,countDis的值也为0.因为Convert.ToInt32(null)= 0。