我正在尝试使用SCOPE_IDENTITY插入最后一个ID,但是我收到了一个错误。 我正在使用SQL Server 2012和Visual Studio Express 2013
这是我的代码
protected void PerformInscription(string sEmail, string sPassword,string sName)
{
bool buserIdAuthenticated = false;
string salt = null;
string passwordHash = pwdManager.GeneratePasswordHash(txtPassword.Text, out salt);
SqlConnection sqlConnection;
sqlConnection = new SqlConnection();
try
{
sqlConnection.ConnectionString = sqlDataSource1.ConnectionString;
string insertStatement = "INSERT INTO [User] "
+ "(email, hash, salt, name) "
+ "VALUES (@email, @hash, @salt, @name);"
+ "SELECT SCOPE_IDENTITY() AS id_user;";
SqlCommand insertCommand = new SqlCommand(insertStatement, sqlConnection);
insertCommand.Parameters.Add("@email", SqlDbType.VarChar, 50).Value = sEmail;
insertCommand.Parameters.Add("@hash", SqlDbType.VarChar, 50).Value = passwordHash;
insertCommand.Parameters.Add("@salt", SqlDbType.VarChar, 50).Value = salt;
insertCommand.Parameters.Add("@nom", SqlDbType.VarChar, 50).Value = sName;
sqlConnection.Open();
int count = insertCommand.ExecuteNonQuery();
int User_ID = Convert.ToInt32(insertCommand.Parameters["@id_user"].Value);
Session["Id_user"] = User_ID;
insertCommand.Dispose();
if (count >= 1)
{
buserIdAuthenticated = true;
Session["userIdAuthenticated"] = buserIdAuthenticated;
Response.Redirect("../pages/Welcome.aspx");
}
}
catch (SqlException ex)
{
lblMessage.Text = ex.Message;
}
finally
{
sqlConnection.Close();
}
}
}
我想捕获最后一个user_id,它被定义为自动增量的标识。
这是我得到的错误
发生了'System.IndexOutOfRangeException'类型的异常 System.Data.dll但未在用户代码中处理。
附加信息:带有ParameterName'@ id_user'的SqlParameter 不包含在此SqlParameterCollection中。
我决定拆分这两个请求。 1个插入和1个选择
SqlConnection sqlConnection;
sqlConnection = new SqlConnection();
try
{
sqlConnection.ConnectionString = sqlDataSource1.ConnectionString;
string insertStatement = "INSERT INTO [User] "
+ "(email, hash, salt, name) "
+ "VALUES (@email, @hash, @salt, @name)";
SqlCommand insertCommand = new SqlCommand(insertStatement, sqlConnection);
insertCommand.Parameters.Add("@email", SqlDbType.VarChar, 50).Value = sEmail;
insertCommand.Parameters.Add("@hash", SqlDbType.VarChar, 50).Value = passwordHash;
insertCommand.Parameters.Add("@salt", SqlDbType.VarChar, 50).Value = salt;
insertCommand.Parameters.Add("@name", SqlDbType.VarChar, 50).Value = sName;
sqlConnection.Open();
int count = insertCommand.ExecuteNonQuery();
insertCommand.Dispose();
if (count >= 1)
{
string selectStatement = "SELECT SCOPE_IDENTITY() AS id_user";
SqlCommand selectCommand = new SqlCommand(selectStatement, sqlConnection);
selectCommand.Parameters.Add("@Id_user", SqlDbType.Int, 0, "Id_user");
int newID = (int)selectCommand.ExecuteScalar();
int User_ID = Convert.ToInt32(selectCommand.Parameters["@Id_user"].Value);
Session["Id_user"] = User_ID;
buserIdAuthenticated = true;
Session["userIdAuthenticated"] = buserIdAuthenticated;
Response.Redirect("../pages/Bienvenue.aspx");
}
}
catch (SqlException ex)
{
lblMessage.Text = ex.Message;
}
finally
{
sqlConnection.Close();
}
}
}
答案 0 :(得分:1)
您不应该在两个查询中拆分查询。您应该在插入查询中选择/设置结果。
我为你做了一个例子:
第一种方法是使用select
private void Method1()
{
string sEmail = "test@test.com";
string passwordHash = "#$@#$@!#@$$@#!#@$!#@$!";
string salt = "????";
string sName = "John";
using (SqlConnection sqlConnection = new SqlConnection(_connectionString))
try
{
sqlConnection.Open();
string insertStatement = "INSERT INTO [User] "
+ "(email, hash, salt, name) "
+ "VALUES (@email, @hash, @salt, @name)"
+ "SELECT SCOPE_IDENTITY()";
using (SqlCommand insertCommand = new SqlCommand(insertStatement, sqlConnection))
{
insertCommand.Parameters.Add("@email", SqlDbType.VarChar, 50).Value = sEmail;
insertCommand.Parameters.Add("@hash", SqlDbType.VarChar, 50).Value = passwordHash;
insertCommand.Parameters.Add("@salt", SqlDbType.VarChar, 50).Value = salt;
insertCommand.Parameters.Add("@name", SqlDbType.VarChar, 50).Value = sName;
int userId = Convert.ToInt32(insertCommand.ExecuteScalar());
Trace.WriteLine("User created with id: " + userId);
}
}
catch (SqlException ex)
{
Trace.WriteLine(ex.Message);
//lblMessage.Text = ex.Message;
}
}
第二种方法是定义输出参数,这样就可以返回多个值。
private void Method2()
{
string sEmail = "test@test.com";
string passwordHash = "#$@#$@!#@$$@#!#@$!#@$!";
string salt = "????";
string sName = "John";
using (SqlConnection sqlConnection = new SqlConnection(_connectionString))
try
{
sqlConnection.Open();
string insertStatement = "INSERT INTO [User] "
+ "(email, hash, salt, name) "
+ "VALUES (@email, @hash, @salt, @name)"
+ "SET @user_id = SCOPE_IDENTITY()";
using (SqlCommand insertCommand = new SqlCommand(insertStatement, sqlConnection))
{
insertCommand.Parameters.Add("@email", SqlDbType.VarChar, 50).Value = sEmail;
insertCommand.Parameters.Add("@hash", SqlDbType.VarChar, 50).Value = passwordHash;
insertCommand.Parameters.Add("@salt", SqlDbType.VarChar, 50).Value = salt;
insertCommand.Parameters.Add("@name", SqlDbType.VarChar, 50).Value = sName;
insertCommand.Parameters.Add("@user_id", SqlDbType.Int).Direction = ParameterDirection.Output;
insertCommand.ExecuteNonQuery();
int userId = Convert.ToInt32(insertCommand.Parameters["@user_id"].Value);
Trace.WriteLine("User created with id: " + userId);
}
}
catch (SqlException ex)
{
Trace.WriteLine(ex.Message);
//lblMessage.Text = ex.Message;
}
}
如果查询是静态的,您可以做的最好的事情就是将这些查询放在存储过程中。这将加快查询速度。
答案 1 :(得分:0)
如评论中所述:
string insertStatement = "INSERT INTO [User] "
+ "(email, hash, salt, name) "
+ "VALUES (@email, @hash, @salt, @name);"
+ "SELECT @id_user = SCOPE_IDENTIY();";
应该是:
string insertStatement = "INSERT INTO [User] "
+ "(email, hash, salt, name) "
+ "VALUES (@email, @hash, @salt, @name);"
+ "SELECT SCOPE_IDENTITY() AS id_user;";
查看SCOPE_IDENTIY
和SCOPE_IDENTITY
之间的区别。
并注意SELECT语句语法的更新。