Question

我需要计算除假期（星期六和星期日）之外的天数。例如，我的开始日期为07/02/2018，结束日期为15/02/2018（格式为dd/MM/yyyy）。我需要计算它们之间的工作日数。有人可以帮帮我吗？这是我的代码：

SimpleDateFormat dateformat3 = new SimpleDateFormat("dd/MM/yyyy");

//Date date12 = dateformat3.parse("17/07/1989");
String date1 = "11/07/2018";
String date2 = "20/07/2018";

// Date date2 = dateformat3.parse("15/10/2007");
Calendar startdate = Calendar.getInstance();
startdate.setTime(dateformat3.parse(date1));
Calendar enddate = Calendar.getInstance();
enddate.setTime(dateformat3.parse(date2));
while (!startdate.after(enddate)) {
    int day = startdate.get(Calendar.DAY_OF_WEEK);
    if ((day != Calendar.SATURDAY) && (day != Calendar.SUNDAY)) {
        workingDays++;
    }
}

我已尝试使用此代码，但未显示任何结果。

Answer 1

你很接近，只需要在循环中增加开始日期。

public static void main(String[] args) throws Exception {
    System.out.println(countDays("07/02/2018", "15/02/2018"));
}

public static int countDays(String startDate, String endDate) throws Exception {
    int workingDays = 0;

    SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");

    Calendar startdate = Calendar.getInstance();
    startdate.setTime(sdf.parse(startDate));
    Calendar enddate = Calendar.getInstance();
    enddate.setTime(sdf.parse(endDate));

    while (!startdate.after(enddate)) {
        int day = startdate.get(Calendar.DAY_OF_WEEK);
        System.out.println(day);
        if ((day != Calendar.SATURDAY) && (day != Calendar.SUNDAY)) {
            workingDays++;
        }

        // increment start date, otherwise while will give infinite loop
        startdate.add(Calendar.DATE, 1);
    }

    return workingDays;
}

正如您所看到的，与我提供的代码（除了删除硬编码值之外）的唯一区别是startdate.add(Calendar.DATE, 1);

Answer 2

我认为你的状况有问题。试试这个

 while (ChronoUnit.DAYS.between(startdate.toInstant(), enddate.toInstant()) > 0) {
    startdate.add(Calendar.DAY_OF_MONTH, 1);
    if (startdate.get(Calendar.DAY_OF_WEEK) != Calendar.SATURDAY && startdate.get(Calendar.DAY_OF_WEEK) != Calendar.SUNDAY) {
      workingDays++;
    }
}

Answer 3

如果您使用的是Java 8，则可以使用：

//Here I change the format of date to make it parsable
String date1 = "2018-07-11";
String date2 = "2018-07-20";

//Parse the date to LocalDate
LocalDate start = LocalDate.parse(date1);
LocalDate end = LocalDate.parse(date2);

//iterate over the list of dates between start and end date, 
//then filter only those who are not equal SATURDAY or SUNDAY, then count the result

long result = Stream.iterate(start, date -> date.plusDays(1))
        .limit(ChronoUnit.DAYS.between(start, end))
        .filter(date -> date.getDayOfWeek() != DayOfWeek.SATURDAY
                && date.getDayOfWeek() != DayOfWeek.SUNDAY
        ).count();

在您的情况下，它将返回7天

Java - 计算除假期（星期六和星期日）之外的天数

3 个答案: