使用for循环将数字推入数组。 （查找给定数量的GCF）

Question

我正在尝试找到我传递给我的函数的任何数字的GCF。 当我提醒我的存储阵列时，我得到的只是0。

为什么我的存储阵列0中唯一的值是？即使循环运行了12次，为什么我的值没有被推入存储阵列？

let gcf = num => {
  let storage = [];
  for (let i = 0; i <= num; i++) {
    // if it divides evenly into num, it is a factor and we want to push it
    // into an array
    if (i % num == 0) {
      storage.push(i);
    } else {
      continue;
    }
  }
  // will sort the array from highest to lowest 
  storage = storage.sort((a, b) => {
    return b - a;
  })
  alert(storage[0]);
  // and return storage[0] for the gcf
}

gcf(12);

Answer 1

你的模运算符是向后的;）

let gcf = num => {
  let storage = [];
  for (let i = 0; i <= num; i++) {
    // if it divides evenly into num, it is a factor and we want to push it
    // into an array
    if (num % i == 0) {
      storage.push(i);
    } else {
      continue;
    }
  }
  // will sort the array from highest to lowest 
  storage = storage.sort((a, b) => {
    return a - b;
  })
  alert(storage[0]);
  // and return storage[0] for the gcf
}

gcf(12);