我有一个名为datasource
的postgresql表,其中jsonb列名为config
。它具有以下结构:
{
"url":"some_url",
"password":"some_password",
"username":"some_username",
"projectNames":[
"project_name_1",
...
"project_name_N"
]
}
我想将嵌套的json数组projectNames
转换为一个映射,并为数组中的每个元素添加一个默认值,所以它看起来像:
{
"url":"some_url",
"password":"some_password",
"username":"some_username",
"projectNames":{
"project_name_1": "value",
...
"project_name_N": "value"
}
}
我使用postgresql jsonb operator projectNames
从表中选择config#>'{projectNames}'
,但我不知道如何执行转换操作。
我认为,我应该使用类似jsonb_object_agg
的内容,但它会将所有数据转换为一行。
我正在使用PostgreSQL 9.6版本。
答案 0 :(得分:1)
您需要首先取消该阵列,然后从中构建一个新的JSON文档。然后你可以把它放回到列中。
update datasource
set config = jsonb_set(config, '{projectNames}', t.map)
from (
select id, jsonb_object_agg(pn.n, 'value') as map
from datasource, jsonb_array_elements_text(config -> 'projectNames') as pn (n)
group by id
) t
where t.id = datasource.id;
以上假设有一个名为id
的主要(或至少是唯一的)列。内部选择将数组转换为地图。
答案 1 :(得分:0)
t=# with c(j) as (values('{
"url":"some_url",
"password":"some_password",
"username":"some_username",
"projectNames":[
"project_name_1",
"project_name_N"
]
}
'::jsonb))
, n as (select j,jsonb_array_elements_text(j->'projectNames') a from c)
select jsonb_pretty(jsonb_set(j,'{projectNames}',jsonb_object_agg(a,'value'))) from n group by j
;
jsonb_pretty
------------------------------------
{ +
"url": "some_url", +
"password": "some_password", +
"username": "some_username", +
"projectNames": { +
"project_name_1": "value",+
"project_name_N": "value" +
} +
}
(1 row)
Time: 19.756 ms
如果是这样,请看:
https://www.postgresql.org/docs/current/static/functions-aggregate.html
https://www.postgresql.org/docs/current/static/functions-json.html