Question

我有这种关系Company hasMany Branch

使用$this->Company->find('all')输出：

(int) 1 => array(
    'Company' => array(
        'id' => '4',
        'nome' => 'Somov',
        'diretores' => 'Marcelo, Carl'
    ),
    'Branch' => array(
        (int) 0 => array(
            'id' => '3',
            'nome' => 'Serra',
            'rua' => 'Rua teste 2 exttttt',
            'numero' => '22',
            'estado' => 'ES',
            'cidade' => 'Etc',
            'cep' => '',
            'responsavel' => '',
            'company_id' => '4',
            'cnpj' => ''
        )
    )
),
(int) 2 => array(
    'Company' => array(
        'id' => '5',
        'nome' => 'Soimpex',
        'diretores' => ''
    ),
    'Branch' => array()
)

）

我想在像这样的json中将其转换为与Highchart一起使用：

[{
            name: NAME OF COMPANY (nome),
            data: NUMBER OF BRANCHS

        }, {
            name: NAME OF COMPANY (nome),
            data: NUMBER OF BRANCHS

        }]

我如何进行此转换？感谢

Answer 1

这将返回一个只有一个结果的json对象。

如果我们使用前面的例子，可以这样做：

$arr = $this->Company->find('all'); // fetch the array
$arr1 = array();
foreach ($arr as $value) {
    $tmp = array();

    $tmp['name'] = $value['Company']['nome'];
    $tmp['data'] = count($value['Branch']);

    $arr1[] = $tmp;
}
return json_encode($arr1);

Answer 2

<?php 
 $sql=mysql_query("select * from Posts limit 20"); 

 $response = array();
 $posts = array();
  while($row=mysql_fetch_array($sql)) 
  { 
    $title=$row['title']; 
    $url=$row['url']; 

    $posts[] = array('title'=> $title, 'url'=> $url);

  } 

    $response['posts'] = $posts;

    $fp = fopen('results.json', 'w');
    fwrite($fp, json_encode($response));
    fclose($fp);


  ?>

这将生成一个名为results.json的文件，其中您的php文件存储在您的在线服务器上，从您的MySQL数据库中获取url和title变量，您可以将变量名称更改为您想要获取的内容。

Answer 3

整个想法就像这样

$arr=$this->Company->find('all'); // fetch the array
$arr1=array();
foreach ($arr as $value) {
    $arr1['name']=$value['Company']['nome'];
    //some more manual transform to desire format
}
return json_encode($arr1);

如何在json中转换这个数组？

3 个答案: