这个问题来自较早的问题。大多数代码来自可能在后续版本的Delphi中使用的建议答案。在D2006中,我没有获得全范围的不透明度,图像的透明部分显示为白色。
图片来自http://upload.wikimedia.org/wikipedia/commons/6/61/Icon_attention_s.png 它在运行时从PNGImageCollection加载到TImage中,因为我发现你必须这样做,因为在保存DFM后图像不会保持不变。出于演示行为的目的,您可能不需要PNGImageCollection,并且可以在设计时将PNG图像加载到TImage中,然后从IDE运行它。
表单上有四个按钮 - 每个按钮设置不同的不透明度值。 Opacity = 0工作正常(paintbox图像不可见,opacity = 16看起来没问题,除了白色背景,不透明度= 64,255相似 - 不透明度似乎在10%左右饱和。
关于什么事情的任何想法?
unit Unit18;
interface
uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, ExtCtrls, pngimage, StdCtrls, Spin, PngImageList;
type
TAlphaBlendForm = class(TForm)
PaintBox1: TPaintBox;
Image1: TImage;
PngImageCollection1: TPngImageCollection;
Button1: TButton;
Button2: TButton;
Button3: TButton;
Button4: TButton;
procedure PaintBox1Paint(Sender: TObject);
procedure FormCreate(Sender: TObject);
procedure Button1Click(Sender: TObject);
procedure Button2Click(Sender: TObject);
procedure Button3Click(Sender: TObject);
procedure Button4Click(Sender: TObject);
private
FOpacity : Integer ;
FBitmap : TBitmap ;
{ Private declarations }
public
{ Public declarations }
end;
var
AlphaBlendForm: TAlphaBlendForm;
implementation
{$R *.dfm}
procedure TAlphaBlendForm.Button1Click(Sender: TObject);
begin
FOpacity:= 0 ;
PaintBox1.Invalidate;
end;
procedure TAlphaBlendForm.Button2Click(Sender: TObject);
begin
FOpacity:= 16 ;
PaintBox1.Invalidate;
end;
procedure TAlphaBlendForm.Button3Click(Sender: TObject);
begin
FOpacity:= 64 ;
PaintBox1.Invalidate;
end;
procedure TAlphaBlendForm.Button4Click(Sender: TObject);
begin
FOpacity:= 255 ;
PaintBox1.Invalidate;
end;
procedure TAlphaBlendForm.FormCreate(Sender: TObject);
begin
Image1.Picture.Assign (PngImageCollection1.Items [0].PNGImage) ;
FBitmap := TBitmap.Create;
FBitmap.Assign(Image1.Picture.Graphic);//Image1 contains a transparent PNG
FBitmap.PixelFormat := pf32bit ;
PaintBox1.Width := FBitmap.Width;
PaintBox1.Height := FBitmap.Height;
end;
procedure TAlphaBlendForm.PaintBox1Paint(Sender: TObject);
var
fn: TBlendFunction;
begin
fn.BlendOp := AC_SRC_OVER;
fn.BlendFlags := 0;
fn.SourceConstantAlpha := FOpacity;
fn.AlphaFormat := AC_SRC_ALPHA;
Windows.AlphaBlend(
PaintBox1.Canvas.Handle,
0,
0,
PaintBox1.Width,
PaintBox1.Height,
FBitmap.Canvas.Handle,
0,
0,
FBitmap.Width,
FBitmap.Height,
fn
);
end;
end.
**此代码(使用graphics32 TImage32)几乎可以工作**
unit Unit18;
interface
uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, ExtCtrls, pngimage, StdCtrls, Spin, PngImageList, GR32_Image;
type
TAlphaBlendForm = class(TForm)
Button1: TButton;
Button2: TButton;
Button3: TButton;
Button4: TButton;
Image321: TImage32;
procedure Button1Click(Sender: TObject);
procedure Button2Click(Sender: TObject);
procedure Button3Click(Sender: TObject);
procedure Button4Click(Sender: TObject);
private
{ Private declarations }
public
{ Public declarations }
end;
var
AlphaBlendForm: TAlphaBlendForm;
implementation
{$R *.dfm}
procedure TAlphaBlendForm.Button1Click(Sender: TObject);
begin
Image321.Bitmap.MasterAlpha := 0 ;
end;
procedure TAlphaBlendForm.Button2Click(Sender: TObject);
begin
Image321.Bitmap.MasterAlpha := 16 ;
end;
procedure TAlphaBlendForm.Button3Click(Sender: TObject);
begin
Image321.Bitmap.MasterAlpha := 64 ;
end;
procedure TAlphaBlendForm.Button4Click(Sender: TObject);
begin
Image321.Bitmap.MasterAlpha := 255 ;
end;
end.
**(更新)此代码(使用graphics32 TImage32)工作**
以下代码成功地在运行时将PNG图像分配给Graphics32.TImage32。具有alpha通道的PNG图像在设计时被加载到TPNGImageCollection(真正有用的组件,因为它允许任意大小的图像的混合)。在表单创建时,它被写入流,然后使用LoadPNGintoBitmap32从流中读取到Image32。完成此操作后,我可以通过分配TImage32.Bitmap.MasterAlpha来控制不透明度。没有打扰OnPaint处理程序。
procedure TAlphaBlendForm.FormCreate(Sender: TObject);
var
FStream : TMemoryStream ;
AlphaChannelUsed : boolean ;
begin
FStream := TMemoryStream.Create ;
try
PngImageCollection1.Items [0].PngImage.SaveToStream (FStream) ;
FStream.Position := 0 ;
LoadPNGintoBitmap32 (Image321.Bitmap, FStream, AlphaChannelUsed) ;
finally
FStream.Free ;
end;
end ;
答案 0 :(得分:5)
正如David对此问题所说,当您将图形分配给位图时,Alpha通道信息会丢失。因此,在分配后将像素格式设置为pf32bit
是没有意义的,除了阻止AlphaBlend
调用失败之外,位图中没有每像素alpha。
但是png对象知道如何在画布上绘制并考虑透明度信息。因此,解决方案将涉及在位图画布上绘制而不是分配图形,然后,由于没有Alpha通道,请从AC_SRC_ALPHA
中删除BLENDFUNCTION
标记。
以下是D2007的工作代码:
procedure TAlphaBlendForm.FormCreate(Sender: TObject);
begin
Image1.Picture.LoadFromFile(
ExtractFilePath(Application.ExeName) + 'Icon_attention_s.png');
FBitmap := TBitmap.Create;
FBitmap.Width := Image1.Picture.Graphic.Width;
FBitmap.Height := Image1.Picture.Graphic.Height;
FBitmap.Canvas.Brush.Color := Color; // background color for the image
FBitmap.Canvas.FillRect(FBitmap.Canvas.ClipRect);
FBitmap.Canvas.Draw(0, 0, Image1.Picture.Graphic);
PaintBox1.Width := FBitmap.Width;
PaintBox1.Height := FBitmap.Height;
end;
procedure TAlphaBlendForm.PaintBox1Paint(Sender: TObject);
var
fn: TBlendFunction;
begin
fn.BlendOp := AC_SRC_OVER;
fn.BlendFlags := 0;
fn.SourceConstantAlpha := FOpacity;
fn.AlphaFormat := 0;
Windows.AlphaBlend(
PaintBox1.Canvas.Handle,
0,
0,
PaintBox1.Width,
PaintBox1.Height,
FBitmap.Canvas.Handle,
0,
0,
FBitmap.Width,
FBitmap.Height,
fn
);
end;
或不使用中间TImage
:
procedure TAlphaBlendForm.FormCreate(Sender: TObject);
var
PNG: TPNGObject;
begin
PNG := TPNGObject.Create;
try
PNG.LoadFromFile(ExtractFilePath(Application.ExeName) + 'Icon_attention_s.png');
FBitmap := TBitmap.Create;
FBitmap.Width := PNG.Width;
FBitmap.Height := PNG.Height;
FBitmap.Canvas.Brush.Color := Color;
FBitmap.Canvas.FillRect(FBitmap.Canvas.ClipRect);
PNG.Draw(FBitmap.Canvas, FBitmap.Canvas.ClipRect);
PaintBox1.Width := FBitmap.Width;
PaintBox1.Height := FBitmap.Height;
finally
PNG.Free;
end;
end;