Question

我正在努力建立一个刺激所得税计算器。我想要取得的进展是：

打印出“您的总收入是多少：”的消息，要求用户以正数字数字输入收入。
阅读他们的输入
制作循环：如果用户输入字符串，则打印“输入您的收入作为整数美元数字”，然后返回步骤1.如果用户输入负数，则打印“您的收入不能否定“，并回到第1步。

4.如果用户已成功输入正数数字，请转到步骤5.

打印出一条消息“你有几个孩子？”
阅读用户的输入。
制作循环：如果用户键入字符串，则打印“您必须输入有效数字”，然后返回步骤5.如果用户键入负数，请打印“您必须输入正数“，然后回到第5步。
如果用户成功输入了正数字，请执行步骤9.
将收入和子女的数字纳入税收计算公式。如果totalTax＆lt; = 0，则打印“您欠税”。如果总税收＆gt; 0，打印“你必须支付[税额]税”。 END

我试图使用下面的代码，但它根本不起作用。

//Record user's income into double list "income"
double i;

//Record user's number of children into double list "kid"
double k;


//if...elif statement to calculate the toatal tax of the user
bool incomeOK = false;
bool kidOK = false;

do
{
    Console.Write("What is your total income : ");
    incomeOK = double.TryParse(Console.ReadLine(), out i);

    if (!incomeOK || i < 0)
    {
        if (!incomeOK)
        {
            Console.WriteLine("Enter your income as a whole-dollar numeric figure.");
        }
        else if (i < 0)
        {
            Console.WriteLine("Your income cannot be negative.");
        }
    }
    else
    {
        Console.Write("How many children do you have: ");
        kidOK = double.TryParse(Console.ReadLine(), out k);

        while (!kidOK || k < 0)
        {
            Console.Write("How many children do you have: ");
            kidOK = double.TryParse(Console.ReadLine(), out k);

            if (kidOK && k >= 0)
            {
                //Calculate the total payable tax of the user
                double totalTax = (i - 10000 - (k * 2000)) * 0.02;

                if (totalTax <= 10000)
                {
                    Console.WriteLine("You owe no tax.");
                    Console.WriteLine("\n\n Hit Enter to exit.");
                    Console.ReadLine();
                }
                else
                {
                    Console.WriteLine("You owe a total of $ " + totalTax + " tax.");
                    Console.WriteLine("\n\n Hit Enter to exit.");
                    Console.ReadLine();
                }
            }

            if (!kidOK || k < 0)
            {
                if (!kidOK)
                {
                    Console.WriteLine("You must enter a valid number.");
                }
                else if (k < 0)
                {
                    Console.WriteLine("You must enter a positive number.");
                }
            }
        }
    }
}
while (!incomeOK || !kidOK);

但是OUTPUT：

你的总收入是多少：sfd
  输入您的收入作为一个整数美元的数字。

按任意键继续......

Answer 1

您需要将其拆分为多个部分。

首先：获得正数

# Training Data
train_X = ...# shape of 1024 x 50
train_Y = ...# shape of 1x50
n_samples = 50
learning_rate = 0.0001
training_epochs = 1000
display_step = 50
# tf Graph Input
X = tf.placeholder("float")
Y = tf.placeholder("float")
# Set model weights
W = tf.Variable(tf.truncated_normal([1024, 1], mean=0.0, stddev=1.0, dtype=tf.float32))
b = tf.Variable(tf.zeros(1, dtype = tf.float32))
# Construct a linear model
pred = tf.add(tf.multiply(X, W), b)
# Mean squared error
cost = tf.reduce_sum(tf.pow(pred-Y, 2))/(2*n_samples)
optimizer = tf.train.GradientDescentOptimizer(learning_rate).minimize(cost)

init = tf.global_variables_initializer()
# Start training
with tf.Session() as sess:
    # Run the initializer
    sess.run(init)
    # Fit all training data
    for epoch in range(training_epochs):
        for (x, y) in zip(train_X, train_Y):
            sess.run(optimizer, feed_dict={X: x, Y: y})
        # Display logs per epoch step
        if (epoch + 1) % display_step == 0:
            c = sess.run(cost, feed_dict={X: train_X, Y: train_Y})
            print("Epoch:", '%04d' % (epoch + 1), "cost=", "{:.9f}".format(c), \
                  "W=", sess.run(W), "b=", sess.run(b))
    print("Optimization Finished!")

第二名：获得孩子数

double i;
double k;

Console.Write("What is your total income : ");

while (!double.TryParse(Console.ReadLine(), out i) || i < 0)
{
    if (i < 0)
    {
        Console.WriteLine("Your income cannot be negative.");
    }
    else 
    {
        Console.WriteLine("Enter your income as a whole-dollar numeric figure.");
    }
}

第三：计算

Console.Write("How many children do you have: ");

while (!double.TryParse(Console.ReadLine(), out k) || k < 0)
{
    if (k < 0)
    {
        Console.WriteLine("You must enter a positive number.");
    }
    else 
    {
        Console.WriteLine("You must enter a valid number.");
    }
}

每当输入错误时，while循环会强制你留在里面。当你离开时，你可以确定输入是正确的。

PS：我会将double totalTax = (i - 10000 - (k * 2000)) * 0.02; if (totalTax <= 10000) { Console.WriteLine("You owe no tax."); Console.WriteLine("\n\n Hit Enter to exit."); Console.ReadLine(); } else { Console.WriteLine("You owe a total of $ " + totalTax + " tax."); Console.WriteLine("\n\n Hit Enter to exit."); Console.ReadLine(); }用于孩子的数量，因为没有任何意义你会有 2.3 孩子。< / p>

C＃while循环不起作用

1 个答案: