基本上我需要这些我在JES中编写的代码,以便不断询问用户多少次和什么组合(这显然是目前的问题),并且只有在输入的数字介于0和9之间时才退出。此刻,如果我输入-3然后输入50则退出。我不确定我是近距离还是远距离。
干杯。
def main()
userInput = requestInteger("Enter a number between 0 and 9...")
while userInput < int(0) :
printNow("Error! Inputs must be between 0 and 9. Please re-enter...")
userInput = requestInteger("Enter a number between 0 and 9...")
while userInput > 9:
printNow("Error! Inputs must be between 0 and 9. Please re-enter...")
userInput = requestInteger("Enter a number between 0 and 9...")
print "Thanks, you have entered: ",userInput,
答案 0 :(得分:1)
您编写的代码完全符合预期......如果您想继续询问用户输入内容,您会想要使用while True
和break
在给出正确输入时将其取出:
while True:
user_input = requestInteger("Enter a number between 0 and 9...")
if not 0 <= user_input <= 9:
printNow("Error! Input must be between 0 and 9. Please re-enter.")
else:
print "Thanks, you've entered: ", user_input
break
答案 1 :(得分:0)
def main():
user_input = int(raw_input("Enter a number between 0 and 9..."))
while user_input not in range(0, 10):
print("Error! Inputs must be between 0 and 9. Please re-enter...")
user_input = int(raw_input("Enter a number between 0 and 9..."))
else:
print "Thanks, you have entered: ",user_input
main()的