我正在研究计算机科学的第二个学期,在我的数据结构课中,我们看到了递归的二叉树。我们必须根据以下Java代码使用递归进行预订后序和顺序遍历:
public class BinaryTree {
Node root;
public void addNode(int key, String name) {
// Create a new Node and initialize it
Node newNode = new Node(key, name);
// If there is no root this becomes root
if (root == null) {
root = newNode;
} else {
// Set root as the Node we will start
// with as we traverse the tree
Node focusNode = root;
// Future parent for our new Node
Node parent;
while (true) {
// root is the top parent so we start
// there
parent = focusNode;
// Check if the new node should go on
// the left side of the parent node
if (key < focusNode.key) {
// Switch focus to the left child
focusNode = focusNode.leftChild;
// If the left child has no children
if (focusNode == null) {
// then place the new node on the left of it
parent.leftChild = newNode;
return; // All Done
}
} else { // If we get here put the node on the right
focusNode = focusNode.rightChild;
// If the right child has no children
if (focusNode == null) {
// then place the new node on the right of it
parent.rightChild = newNode;
return; // All Done
}
}
}
}
}
// Traversals recursion methods
public void inOrderTraverseTree(Node focusNode) {
}
public void preorderTraverseTree(Node focusNode) {
}
public void postOrderTraverseTree(Node focusNode) {
}
//******************************************************************
public Node findNode(int key) {
// Start at the top of the tree
Node focusNode = root;
// While we haven't found the Node
// keep looking
while (focusNode.key != key) {
// If we should search to the left
if (key < focusNode.key) {
// Shift the focus Node to the left child
focusNode = focusNode.leftChild;
} else {
// Shift the focus Node to the right child
focusNode = focusNode.rightChild;
}
// The node wasn't found
if (focusNode == null)
return null;
}
return focusNode;
}
public static void main(String[] args) {
BinaryTree theTree = new BinaryTree();
theTree.addNode(50, "Boss");
theTree.addNode(25, "Vice President");
theTree.addNode(15, "Office Manager");
theTree.addNode(30, "Secretary");
theTree.addNode(75, "Sales Manager");
theTree.addNode(85, "Salesman 1");
// Different ways to traverse binary trees
theTree.inOrderTraverseTree(theTree.root);
theTree.preorderTraverseTree(theTree.root);
theTree.postOrderTraverseTree(theTree.root);
// Find the node with key 75
System.out.println("\nNode with the key 75");
System.out.println(theTree.findNode(75));
}
}
class Node {
int key;
String name;
Node leftChild;
Node rightChild;
Node(int key, String name) {
this.key = key;
this.name = name;
}
public String toString() {
return name + " has the key " + key;
/*
* return name + " has the key " + key + "\nLeft Child: " + leftChild +
* "\nRight Child: " + rightChild + "\n";
*/
}
}
有人可以解释一下这些交易是如何运作的,以及如何对它们进行编码?
答案 0 :(得分:1)
在线有一些很棒的二叉树可视化,所以你可以更好地理解它,但这里有一些我使用的图像。
public void inOrderTraverseTree(Node focusNode) {
if (focusNode != null) {
// Traverse the left node
inOrderTraverseTree(focusNode.leftChild);
// Visit the currently focused on node
System.out.println(focusNode);
// Traverse the right node
inOrderTraverseTree(focusNode.rightChild);
}
}
public void postOrderTraverseTree(Node focusNode) {
if (focusNode != null) {
postOrderTraverseTree(focusNode.leftChild);
postOrderTraverseTree(focusNode.rightChild);
System.out.println(focusNode);
}
}
public void preorderTraverseTree(Node focusNode) {
if (focusNode != null) {
System.out.println(focusNode);
preorderTraverseTree(focusNode.leftChild);
preorderTraverseTree(focusNode.rightChild);
}
}