Question

我有三个阵列。

其中一个包含我将要测试的值。另外两个是对象数组，可能包含我在name键下的第一个数组的值。

const myArray = ["foo", "bar"];

const testArray1 = [
    {name: "foo"},
    {name: "bar"},
    {name: "something else"}
]

const testArray2 = [
    {name: "foo"},
    {name: "rab"},
    {name: "something else"}
]

我正在尝试编写一个条件，只有当测试的数组包含我的第一个数组的所有值时才返回true。

使用相同的例子，它会给我这样的东西：

if (testArray1.containsAll(myArray)) // true
if (testArray2.containsAll(myArray)) // false

解决此问题的最佳方法是什么？

谢谢，任何帮助非常感谢

Answer 1

使用array.prototype.every和array.prototype.find，它应该是：

const myArray = ["foo", "bar"];

const testArray1 = [
    {name: "foo"},
    {name: "bar"},
    {name: "something else"}
];

const testArray2 = [
    {name: "foo"},
    {name: "rab"},
    {name: "something"}
];

console.log(myArray.every(s => testArray1.find(o => o.name === s)));
console.log(myArray.every(s => testArray2.find(o => o.name === s)));

Answer 2

可以使用，每一个和一些。这些只返回true / false

＆＃13;

const myArray = ["foo", "bar"];

const testArray1 = [
    {name: "foo"},
    {name: "bar"},
    {name: "something else"}
]

const testArray2 = [
    {name: "foo"},
    {name: "rab"},
    {name: "something else"}
]

let result1 = testArray1.every(item => myArray.some(array => item.name == array))
let result2 = testArray2.every(item => myArray.some(array => item.name == array))

console.log('result1', result1)
console.log('result2', result2)

＆＃13;

Answer 3

检查一下。可能不是最好的方式，但工作得很好。

const myArray = ["foo", "bar"];

const testArray1 = [
    {name: "foo"},
    {name: "bar"},
    {name: "something else"}
]

const testArray2 = [
    {name: "foo"},
    {name: "rab"},
    {name: "something else"}
]
let aFlag = testArray1.filter( a =>  myArray.includes(a.name)).length === myArray.length;
let bFlag = testArray2.filter( a =>  myArray.includes(a.name)).length === myArray.length;
console.log(aFlag, bFlag)

搜索对象数组中的所有值

3 个答案: