Question

我有以下任务要做，如果有任何机会我会感激一些帮助，以尽可能有效的方式。我需要比较来自对象数组（来自Laravel Query Builder连接查询）的值与数组值。

对象由数据库存储值组成：

0 => array:2 [
  0 => {#912
    +"addition_id": 1
    +"valid_from": "2015-09-13 00:00:00"
    +"valid_to": "2015-09-19 00:00:00"
    +"price": "0.00"
    +"mode": 0
    +"alias": "Breakfast"
  }
  1 => {#911
    +"addition_id": 2
    +"valid_from": "2015-09-13 00:00:00"
    +"valid_to": "2015-09-19 00:00:00"
    +"price": "10.00"
    +"mode": 1
    +"alias": "Dinner"
  }

while数组包含新数据，由我的方法处理。

0 => array:3 [
  0 => array:6 [
    "id" => 1
    "alias" => "Breakfast"
    "price" => "0.00"
    "mode" => 0
    "created_at" => "2015-09-12 21:25:03"
    "updated_at" => "2015-09-12 21:25:03"
  ]
  1 => array:6 [
    "id" => 2
    "alias" => "Dinner"
    "price" => "10.00"
    "mode" => 1
    "created_at" => "2015-09-12 21:25:18"
    "updated_at" => "2015-09-12 21:25:18"
  ]
  2 => array:6 [
    "id" => 3
    "alias" => "Sauna Access"
    "price" => "50.00"
    "mode" => 0
    "created_at" => "2015-09-12 21:25:35"
    "updated_at" => "2015-09-12 21:25:35"
  ]
 ]

现在，我需要做的是找出数组中对象的位置（比较 id 与 addition_id ）并返回它。

如果没有两个嵌套的foreach循环，有没有办法做到这一点？我认为可以通过array_filter以某种方式实现智能，但我并不确定如何编写高效的回调（这里是初学者）。

我唯一能解决这个问题的方法是：

private function compareAdditions(array $old,array $new)
{
    $difference = $new;

    foreach($new as $key => $value) {
        foreach($old as $oldEntry) {
            if($oldEntry->addition_id == $value['id']) {
                unset($difference[$key]);
            }
        }
    }

    return $difference;
}

但我真的很想在没有两个foreach循环的情况下做到这一点。非常感谢帮助：）

Answer 1

这可能有点矫枉过正，但它使用了我在每个项目中编写的函数，正是针对这些情况：

function additionals($original, $additions) {
    $nonExisiting = [];
    //convert all the objects in arrays
    $additions = json_decode(json_encode($additions), true);
    //create an index
    $index = hashtable2list($original, 'id');
    for(reset($additions); current($additions); next($additions)) {
        $pos = array_search(current($additions)['addition_id'], $index);
        if($pos !== false) {
            //We could replace the originals with the additions in the same loop and save resources
            //$original[$pos] = current($additions);
        } else {
            $nonExisiting[] = current($additions);
        }
    }
    return $nonExisiting;
}

function hashtable2list( $hashtable, $key ){
    $array = [];
    foreach($hashtable as $entry) {
        if( is_array($entry) && isset($entry[$key])) {
            $array[] = $entry[$key];
        } elseif( is_object($entry) && isset($entry->$key)  ) {
            $array[] = $entry->$key;
        } else {
            $array[] = null;
        }
    }
    return $array;
}

在PHP中搜索多维数组值的对象数组

1 个答案: