Question

我正在进行一项任务，我必须在屏幕上实例化几个不同的对象并对其进行格式化。我无法正确输出字符串;代替文本我得到像这样的输出

run:
First Name  Last Name   Student ID Number   
studentdemo.StudentDemo@6d06d69c
studentdemo.StudentDemo@7852e922
studentdemo.StudentDemo@4e25154f
studentdemo.StudentDemo@70dea4e
studentdemo.StudentDemo@5c647e05
BUILD SUCCESSFUL (total time: 0 seconds)

这是我的主要

package studentdemo;
public class MainStudent {public static void main(String[] args) {
StudentDemo student1 = new StudentDemo("Peter\t","Adams\t","123546\t");
StudentDemo student2 = new StudentDemo("James\t","Clark\t","654332\t");
StudentDemo student3 = new 
StudentDemo("Christopher\t","Colombo\t","223344\t");
StudentDemo student4 = new StudentDemo("Amy\t","Tan\t","997766\t");
StudentDemo student5 = new 
StudentDemo("Marry\t","Madison\t","6543321\t");
System.out.println("First Name\t"+"Last Name\t"+"Student ID Number\t");
System.out.println(student1);
System.out.println(student2);
System.out.println(student3);
System.out.println(student4);
System.out.println(student5);

}

}

这是我的另一个班级

package studentdemo;
public class StudentDemo {
private String firstName;
private String lastName;
private String studentIdNumber;

public StudentDemo(String firstName, String lastName, String 
studentIdNumber) {
this.firstName = firstName;
this.lastName = lastName;
this.studentIdNumber = studentIdNumber;
}

public void setFirstName(String firstName) {
this.firstName = firstName;
}

public String getFirstName() {
return firstName;
}

public void setLastName(String lastName) {
this.lastName = lastName;
}

public String getLastName() {
    return lastName;
}
public void setStudentIdNubmer(String studentIdNumber) {
    this.studentIdNumber = studentIdNumber;
}
public String getStudentIdNumber() {
    return studentIdNumber;
}
}

我做错了什么？`

Answer 1

这是因为您正在尝试打印对象（student1）而不是对象的属性。

请尝试：

的System.out.println（student1.getFirstName（）+ “\ t” 的+ student1.getLastName（）+ “\ t” 的+ student1.getStudentIdNumber（））;

而不是：

System.out.println(student1);

希望这能解决您的问题。

Answer 2

您需要输出如下：

System.out.println(student1.getFirstName() + " " + student1.getLastName());

Answer 3

更好的解决方案是覆盖StudentDemo类中的toString（）方法。例如：

public class StudentDemo {
    ...
    @Override
    public String toString() {
        return this.firstName + " " + this.lastName + " " + this.studentIdNumber;
    }
}

现在当你创建一个新的学生对象，即StudentDemo student1 = new StudentDemo();时，如果你做System.out.prntln(student1);，将自动调用toString（）方法。

如何在屏幕上获取输出对象？

3 个答案: