Question

我想在Turtle屏幕上输出一个变量。但随着变量的变化，之前的值仍然在屏幕上。因此，这些值是重叠的。方法turtle.clear()无法解决问题，因为它会导致值在屏幕上闪烁。

# -*- coding: utf-8 -*-

import turtle
from math import *

s = turtle.Screen()
body = turtle.Turtle()
time_t = turtle.Turtle()
time_t.penup() # For time output
time_t.ht()

def Motion(A=100, omega=5, N=2):
    n = 0
    t = 0

    def x_pos(t):
        return A*cos(0.5*omega*t)  # x

    def y_pos(t):
        return A*sin(1*omega*t)  # Кy

    body.setposition(x_pos(t),y_pos(t))
    body.pendown()

    while n<N:
        body.setposition(x_pos(t),y_pos(t))
        t = round(t + 0.01,2)
        time_t.setposition(200,200)  # In this position I want to output variable
        time_t.write("t = " + str(t))  # Show the time variable t on screen
        if int(round(t / (2*pi/omega),2)) == n + 1:
              n =  n + 1


body.penup()
body.color('red')
body.shape('circle')
Motion()
turtle.done()

Answer 1

我们可以采取一些措施来改善这种状况。第一种是使用乌龟的撤消功能删除旧时信息作为清除它的方法。其次，我们可以使用tracer()和update()来控制动画更新，以便控制闪烁：

from turtle import Turtle, Screen
from math import pi, sin, cos

screen = Screen()

body = Turtle(shape="circle")
body.color('red')
body.penup()

time_t = Turtle(visible=False)  # For time output
time_t.penup()
time_t.setposition(200, 200)  # In this position I want to output variable
time_t.write("t = " + str(0))

screen.tracer(0)  # Control animation updates ourself

def Motion(A=100, omega=5, N=2):
    n = 0
    t = 0

    def x_pos(t):
        return A * cos(0.5 * omega * t)  # x

    def y_pos(t):
        return A * sin(1 * omega * t)  # Ky

    body.setposition(x_pos(t), y_pos(t))
    body.pendown()

    while n < N:
        body.setposition(x_pos(t), y_pos(t))

        t = round(t + 0.01, 2)
        time_t.undo()  # undraw the last time update
        time_t.write("t = " + str(t))  # Show the time variable t on screen
        screen.update()

        if int(round(t / (2 * pi / omega), 2)) == n + 1:
            n = n + 1

Motion()

screen.exitonclick()

BTW，非常酷的乌龟使用！让我们更进一步：让运动连续;在动画期间的任何时候启用退出点击;不要让尸体龟可见，直到它处于初始位置;提高字体大小，以便我们看到时间：

from turtle import Turtle, Screen
from math import pi, sin, cos

def motion():
    global n, t
    body.setposition(x_pos(t), y_pos(t))

    t = round(t + 0.01, 2)
    time_t.undo()  # undraw the last time update
    time_t.write("t = " + str(t), font=font)  # Show the time variable t on screen
    screen.update()

    if int(round(t / (2 * pi / omega), 2)) == n + 1:
        n = n + 1
        if (n >= N):
            n = t = 0

    screen.ontimer(motion, 10)

def x_pos(t):
    return A * cos(0.5 * omega * t)  # x

def y_pos(t):
    return A * sin(1 * omega * t)  # Ky

A = 100
omega = 5
N = 2
n = t = 0

font = ("Arial", 12, "normal")

screen = Screen()
screen.tracer(0)  # Control animation updates ourself

body = Turtle(shape="circle", visible=False)
body.color('red')
body.penup()
body.setposition(x_pos(t), y_pos(t))
body.pendown()
body.showturtle()

time_t = Turtle(visible=False)  # For time output
time_t.penup()
time_t.setposition(200, 200)  # In this position I want to output variable
time_t.write("t = " + str(0))

screen.ontimer(motion, 100)

screen.exitonclick()

如何在龟屏上输出变量？

1 个答案: